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Posts tagged unspecified-behavior
When doing something simple such as this int a=1; int b=2; int c=3; printf("%d\n", a + b * c); then I was told that operator precedence guarantees that the code is equivalent to a + (b * c)...
Consider the following code: #include <stdio.h> int main() { int a = 5; int b; ++*(&b + 1); printf("%d\n", a); return 0; } The output is as expected: 6 ...
I'm experimenting with different operators and have a hard time understanding the outcome of certain expressions. I try to combine the ++ operators with other operators such as assignment in the sa...
