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Create a list of Niven numbers in Python
There's this new challenge on Code Golf CD and I'm using Python to do it. A little bit of golfing already took place, so the code might look a bit messy for you. Anyway, I'm proud of what I've written so far:
def g(n):
s=0;t=n
while t>0:s+=t%10;t//=10
return n%s==0
def f(n):
a=[]
for i in range(1,n+2):
while not g(i):
i+=1;continue
a.append(i)
return a
First function checks for Niven numbers, the second one creates a list for them. Problem that occurred is something like this since I can't word it.
If I'd input 14 into the function, I should get:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 18, 20, 21, 24]
But instead, I'd get this:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 12, 18, 18, 18]
Any ways to fix this?
2 answers
The way your code handles the variable i within the for loop seems to indicate a wrong understanding of the meaning of
for i in range(1,n+2):
range(1,n+2) will provide an object of type range. This object represents the sequence of numbers from 1 to (not including) n+2. At the begin of each iteration the next element from that sequence is fetched and assigned to i, no matter what happened to i in between.
In other words, you can not "skip" elements from the range object just by incrementing i within the for loop. You can see this with the help of the following example code:
for i in range(3):
print("Value of i at start of loop body: i = ", i)
i += 20
print("Value of i after modification: i = ", i)
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The following users marked this post as Works for me:
| User | Comment | Date |
|---|---|---|
| General Sebast1an | (no comment) | Aug 20, 2022 at 05:52 |
Think of what your for loop is doing, specifically at iterations 11 and 12.
for i in range(1,n+2):
while not g(i):
i+=1;continue
a.append(i)
In pseudo instructions:
-
for-loop iteration 11
- i = 11
- while-loop:
- check not g(i) (i = 11, so it's true)
- i += 1
- check not g(i) (i = 12, so it's false)
- append i (appends 12)
-
for-loop iteration 12
- i = 12
- while-loop:
- check not g(i) (i = 12, so it's false)
- append i (appends 12)
That is, the problem is that as it is written, it is "for i from 1 to n + 2, get the smallest Niven number greater than i" which is probably not what you want.
One possible fix to this is just to separate the list index counter and the Niven number counter. The implementation is left as an exercise to the reader.
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