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Welcome to Software Development on Codidact!

Will you help us build our independent community of developers helping developers? We're small and trying to grow. We welcome questions about all aspects of software development, from design to code to QA and more. Got questions? Got answers? Got code you'd like someone to review? Please join us.

Posts by Emily‭

5 posts
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Q&A Alternatives to `EXPLAIN ANALYZE` for queries that won't complete

I have a large and complex PostgreSQL SELECT query that I would like to make faster. EXPLAIN suggests it should run quickly, with the worst parts being scans of a few thousand rows. When run, it do...

2 answers  ·  posted 1y ago by Emily‭  ·  last activity 1y ago by matthewsnyder‭

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Q&A How do I share a type between a client and server, but make a specific field optional for one and required for the other?

Let's say I have a client/server application with a data structure on the server side: type User = { name: string; superSecretGovernmentIdNumber: string; }; These fields are both non-nul...

2 answers  ·  posted 1y ago by Emily‭  ·  last activity 6mo ago by Jacob Raihle‭

Question typescript
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Q&A How do I share a type between a client and server, but make a specific field optional for one and required for the other?

This can be done using conditional types. I defined these helper types: enum Role { server, client }; type PossiblyHiddenFromClients<R extends Role, T> = T | (R extends Role.client ? un...

posted 1y ago by Emily‭

Answer
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Q&A Why does bash seem to parse `sh -c` commands differently when called via `execl`?

When I do this in a shell: $ /bin/sh -c 'echo hello world' hello world it's my understanding that I'm running a process with argv = {"/bin/sh", "-c", "echo hello world"}. That is, the quotes c...

1 answer  ·  posted 8mo ago by Emily‭  ·  last activity 8mo ago by Emily‭

Question bash execl
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+4 −0
Q&A Why does bash seem to parse `sh -c` commands differently when called via `execl`?

Because execl's first argument isn't argv[0]. execl("/bin/sh", "-c", ...) runs the executable /bin/sh, but sets its argv[0] to "-c", as if one had created a link called -c pointing at it and run t...

posted 8mo ago by Emily‭

Answer