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Code Reviews Counting Sundays without Python datetime module

The problem You are given the following information, but you may prefer to do some research for yourself. 1 Jan 1900 was a Monday. Thirty days has September, April, June and November. All t...

1 answer · posted 3y ago by Vinicius Brasil‭ · edited 3y ago by hkotsubo‭

Question python date

#3: Post edited by

hkotsubo‭ · 2021-12-21T06:24:31Z (almost 3 years ago)
Using the correct module name

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~~Counting Sundays without Python date module~~

Counting Sundays without Python datetime module

# The problem
> You are given the following information, but you may prefer to do some
> research for yourself.
>
> * 1 Jan 1900 was a Monday.
> * Thirty days has September, April, June and November. All the rest have thirty-one, saving February alone, which has twenty-eight, rain
> or shine.
> * And on leap years, twenty-nine. A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
>
> How many Sundays fell on the first of the month during the twentieth
> century (1 Jan 1901 to 31 Dec 2000)?
# The solution
```
def is_century(year):
return year % 100 == 0
def is_leap_year(year):
if is_century(year):
return year % 400 == 0
else:
return year % 4 == 0
def get_day_count(year, month):
if month == 2 and is_leap_year(year):
return 29
elif month == 2:
return 28
elif month in [4, 6, 9, 11]:
return 30
else:
return 31
def solution(start_day, start_month, start_year, end_day, end_month, end_year):
current_day, current_month, current_year = start_day, start_month, start_year
days = 0
sundays = 0
while current_day != end_day or current_month != end_month or current_year != end_year:
if days % 7 == 0 and current_day == 1:
sundays += 1
days += 1
if current_day == get_day_count(current_year, current_month):
current_day = 1
if current_month == 12:
current_month = 1
current_year += 1
else:
current_month += 1
else:
current_day += 1
return sundays
print(solution(1, 1, 1901, 31, 12, 2000))
```
~~I solved Project Euler Problem 19 with Python. My goal was to solve this without the `date` module, and handling the calendar part on my own.~~
As the problem states the start date is a Monday, I counted the next Mondays that fell on the first of the month using this condition: `if days % 7 == 0 and current_day == 1:`, being `days` the number of days I counted so far inside the loop.
What can be improved? Have I overcomplicated some part of the code?

# The problem
> You are given the following information, but you may prefer to do some
> research for yourself.
>
> * 1 Jan 1900 was a Monday.
> * Thirty days has September, April, June and November. All the rest have thirty-one, saving February alone, which has twenty-eight, rain
> or shine.
> * And on leap years, twenty-nine. A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
>
> How many Sundays fell on the first of the month during the twentieth
> century (1 Jan 1901 to 31 Dec 2000)?
# The solution
```
def is_century(year):
return year % 100 == 0
def is_leap_year(year):
if is_century(year):
return year % 400 == 0
else:
return year % 4 == 0
def get_day_count(year, month):
if month == 2 and is_leap_year(year):
return 29
elif month == 2:
return 28
elif month in [4, 6, 9, 11]:
return 30
else:
return 31
def solution(start_day, start_month, start_year, end_day, end_month, end_year):
current_day, current_month, current_year = start_day, start_month, start_year
days = 0
sundays = 0
while current_day != end_day or current_month != end_month or current_year != end_year:
if days % 7 == 0 and current_day == 1:
sundays += 1
days += 1
if current_day == get_day_count(current_year, current_month):
current_day = 1
if current_month == 12:
current_month = 1
current_year += 1
else:
current_month += 1
else:
current_day += 1
return sundays
print(solution(1, 1, 1901, 31, 12, 2000))
```
I solved Project Euler Problem 19 with Python. My goal was to solve this without the `datetime` module, and handling the calendar part on my own.
As the problem states the start date is a Monday, I counted the next Mondays that fell on the first of the month using this condition: `if days % 7 == 0 and current_day == 1:`, being `days` the number of days I counted so far inside the loop.
What can be improved? Have I overcomplicated some part of the code?

#2: Post edited by

hkotsubo‭ · 2021-06-15T19:40:06Z (over 3 years ago)
fixed typo and added tag

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Counting Sundays without Python date module

~~# The probelm~~
> You are given the following information, but you may prefer to do some
> research for yourself.
>
> * 1 Jan 1900 was a Monday.
> * Thirty days has September, April, June and November. All the rest have thirty-one, saving February alone, which has twenty-eight, rain
> or shine.
> * And on leap years, twenty-nine. A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
>
> How many Sundays fell on the first of the month during the twentieth
> century (1 Jan 1901 to 31 Dec 2000)?
# The solution
```
def is_century(year):
return year % 100 == 0
def is_leap_year(year):
if is_century(year):
return year % 400 == 0
else:
return year % 4 == 0
def get_day_count(year, month):
if month == 2 and is_leap_year(year):
return 29
elif month == 2:
return 28
elif month in [4, 6, 9, 11]:
return 30
else:
return 31
def solution(start_day, start_month, start_year, end_day, end_month, end_year):
current_day, current_month, current_year = start_day, start_month, start_year
days = 0
sundays = 0
while current_day != end_day or current_month != end_month or current_year != end_year:
if days % 7 == 0 and current_day == 1:
sundays += 1
days += 1
if current_day == get_day_count(current_year, current_month):
current_day = 1
if current_month == 12:
current_month = 1
current_year += 1
else:
current_month += 1
else:
current_day += 1
return sundays
print(solution(1, 1, 1901, 31, 12, 2000))
```
I solved Project Euler Problem 19 with Python. My goal was to solve this without the `date` module, and handling the calendar part on my own.
As the problem states the start date is a Monday, I counted the next Mondays that fell on the first of the month using this condition: `if days % 7 == 0 and current_day == 1:`, being `days` the number of days I counted so far inside the loop.
What can be improved? Have I overcomplicated some part of the code?

# The problem
> You are given the following information, but you may prefer to do some
> research for yourself.
>
> * 1 Jan 1900 was a Monday.
> * Thirty days has September, April, June and November. All the rest have thirty-one, saving February alone, which has twenty-eight, rain
> or shine.
> * And on leap years, twenty-nine. A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
>
> How many Sundays fell on the first of the month during the twentieth
> century (1 Jan 1901 to 31 Dec 2000)?
# The solution
```
def is_century(year):
return year % 100 == 0
def is_leap_year(year):
if is_century(year):
return year % 400 == 0
else:
return year % 4 == 0
def get_day_count(year, month):
if month == 2 and is_leap_year(year):
return 29
elif month == 2:
return 28
elif month in [4, 6, 9, 11]:
return 30
else:
return 31
def solution(start_day, start_month, start_year, end_day, end_month, end_year):
current_day, current_month, current_year = start_day, start_month, start_year
days = 0
sundays = 0
while current_day != end_day or current_month != end_month or current_year != end_year:
if days % 7 == 0 and current_day == 1:
sundays += 1
days += 1
if current_day == get_day_count(current_year, current_month):
current_day = 1
if current_month == 12:
current_month = 1
current_year += 1
else:
current_month += 1
else:
current_day += 1
return sundays
print(solution(1, 1, 1901, 31, 12, 2000))
```
I solved Project Euler Problem 19 with Python. My goal was to solve this without the `date` module, and handling the calendar part on my own.
As the problem states the start date is a Monday, I counted the next Mondays that fell on the first of the month using this condition: `if days % 7 == 0 and current_day == 1:`, being `days` the number of days I counted so far inside the loop.
What can be improved? Have I overcomplicated some part of the code?

#1: Initial revision by

Vinicius Brasil‭ · 2021-06-15T17:37:27Z (over 3 years ago)

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Markdown

Counting Sundays without Python date module

# The probelm

> You are given the following information, but you may prefer to do some
> research for yourself.
> 
> * 1 Jan 1900 was a Monday.
> * Thirty days has September, April, June and November. All the rest have thirty-one, saving February alone, which has twenty-eight, rain
> or shine.
> * And on leap years, twenty-nine. A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
> 
> How many Sundays fell on the first of the month during the twentieth
> century (1 Jan 1901 to 31 Dec 2000)?

# The solution

```
def is_century(year):
	return year % 100 == 0

def is_leap_year(year):
	if is_century(year):
		return year % 400 == 0 
	else:
		return year % 4 == 0

def get_day_count(year, month):
	if month == 2 and is_leap_year(year):
		return 29
	elif month == 2:
		return 28
	elif month in [4, 6, 9, 11]:
		return 30
	else:
		return 31

def solution(start_day, start_month, start_year, end_day, end_month, end_year):
	current_day, current_month, current_year = start_day, start_month, start_year
	days = 0
	sundays = 0
	
	while current_day != end_day or current_month != end_month or current_year != end_year:
		if days % 7 == 0 and current_day == 1:
			sundays += 1

		days += 1

		if current_day == get_day_count(current_year, current_month):
			current_day = 1
			if current_month == 12:
				current_month = 1
				current_year += 1
			else:
				current_month += 1
		else:
			current_day += 1
	
	return sundays

print(solution(1, 1, 1901, 31, 12, 2000))
```

I solved Project Euler Problem 19 with Python. My goal was to solve this without the `date` module, and handling the calendar part on my own.

As the problem states the start date is a Monday, I counted the next Mondays that fell on the first of the month using this condition: `if days % 7 == 0 and current_day == 1:`, being `days` the number of days I counted so far inside the loop.

What can be improved? Have I overcomplicated some part of the code?

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