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This suggested edit was approved and applied to the post over 1 year ago by Alexei‭.

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How to resolve a "ValueError: dimension 't' already exists as a scalar variable" arising when I am using xarray.Dataset.assign_coords()?
  • I have the following `xarray.Dataset`:
  • `d: <xarray.Dataset>`
  • `Dimensions: (x: 79, y: 63, t: 1)`
  • `Coordinates:`
  • `* x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35`
  • ` * y (y) float64 59.29 58.35 57.41 56.47 ... 3.765 2.824 1.882 0.9412`
  • `* t (t) int32 0`
  • `Data variables:`
  • u (x, y, t) float64 0.0 0.0 0.0 0.0 0.0 0.0 ... 0.0 0.0 0.0 0.0 0.0
  • v (x, y, t) float64 -0.0 -0.0 -0.0 -0.0 -0.0 ... -0.0 -0.0 -0.0 -0.0
  • chc (x, y, t) float64 1.0 1.0 1.0 1.0 1.0 1.0 ... 1.0 1.0 1.0 1.0 1.0
  • `Attributes: (2)`
  • I'm trying to assign new values to the coordinate `t` using `.assign_coords()`:
  • `d = d.assign_coords(t = 0.123)`
  • I receive an error: `ValueError: dimension 't' already exists as a scalar variable`
  • How to resolve the error and assign a new value to the `t` coordinate?
  • -------------------
  • I have tried the solutions to the similar problems posted on StackOverflow, such as 1) `assign_coords` is not an inplace operation, 2) recreate `t` as a coordinate and then assign the value to it, 3) change the type of `t` to `float`. Also, I suspected that the asterisk next to the name of my coordinate `t` has something to do with the error. But I don't know what the asterisk means, I could only find that it is a reference to something called "proper coordinate".
  • P.S. I am sorry for the formatting of my code: I didn't know how to code-format a chunk of code spanning several lines.
  • I have the following [xarray](https://docs.xarray.dev/en/stable/index.html) `Dataset`:
  • ```
  • d: <xarray.Dataset>
  • Dimensions: (x: 79, y: 63, t: 1)
  • Coordinates:
  • * x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35
  • * y (y) float64 59.29 58.35 57.41 56.47 ... 3.765 2.824 1.882 0.9412
  • * t (t) int32 0
  • Data variables:
  • u (x, y, t) float64 0.0 0.0 0.0 0.0 0.0 0.0 ... 0.0 0.0 0.0 0.0 0.0
  • v (x, y, t) float64 -0.0 -0.0 -0.0 -0.0 -0.0 ... -0.0 -0.0 -0.0 -0.0
  • chc (x, y, t) float64 1.0 1.0 1.0 1.0 1.0 1.0 ... 1.0 1.0 1.0 1.0 1.0
  • Attributes: (2)
  • ```
  • When I try to assign new values to the coordinate `t`, using `d = d.assign_coords(t = 0.123)`, I receive an error:
  • `ValueError: dimension 't' already exists as a scalar variable`
  • How can I resolve the error and assign a new value to the `t` coordinate?
  • I have tried the solutions to the similar problems posted on Stack Overflow, such as
  • * `assign_coords` is not an inplace operation
  • * recreate `t` as a coordinate and then assign the value to it
  • * change the type of `t` to `float`
  • I suspect that the asterisk next to the name of my coordinate `t` has something to do with the error. But I don't understand what it means; I could only find that it is a reference to something called "proper coordinate".

Suggested over 1 year ago by Karl Knechtel‭