Welcome to Software Development on Codidact!

Will you help us build our independent community of developers helping developers? We're small and trying to grow. We welcome questions about all aspects of software development, from design to code to QA and more. Got questions? Got answers? Got code you'd like someone to review? Please join us.

Review Suggested Edit

You can't approve or reject suggested edits because you haven't yet earned the Edit Posts ability.

~~Python regex capture groups dynamically~~

Regex to get text outside brackets

~~Hello World!~~
~~I am trying to capture the content outside square brackets in groups. So, this is my regex:~~
```
(.*)\[.*?\](.*)
```
And it works perfectly for a simple string like this:
```
testing_[_is_]_done
```
This is the sample script I am using:
~~```~~
import re
groups = re.match(r"(.*)\[.*?\](.*)", "testing_[_is_]_done").groups()
print(groups)
```
And this is the output I am getting:
~~```~~
('testing_', '_done')
```
Now, the problem is, for some strings there will be multiple open-close square brackets and I am want to capture everything outside of square brackets into groups but I am not able to figure out how to come up with regex which can do this job.
This is the example:
```
testing_[_is_]_done_([but need to])_handle_[this]_scenario_as_well
```
And ideally, I want to capture everything outside of brackets in groups, like this:
```
('testing_', '_done_(', ')_handle_', '_scenario_as_well')
```
~~Because it can be one or n number of open-close brackets, so I am looking for a dynamic regex, but so far I am not able to find anything on it.~~
~~If anyone of you have any idea on how to get this done. Kindly let me know.~~
~~Thank you.~~

I am trying to capture the content outside square brackets in groups, using this regex:
```
(.*)\[.*?\](.*)
```
And it works perfectly for a simple string like this:
```
testing_[_is_]_done
```
This is the sample script I am using:
```python
import re
groups = re.match(r"(.*)\[.*?\](.*)", "testing_[_is_]_done").groups()
print(groups)
```
And this is the output I am getting:
```none
('testing_', '_done')
```
But for some strings there will be multiple open-close square brackets and I want to capture everything outside of square brackets into groups but I am not able to figure out how to come up with regex which can do this job.
This is the example:
```
testing_[_is_]_done_([but need to])_handle_[this]_scenario_as_well
```
And ideally, I want to capture everything outside of brackets in groups, like this:
```
('testing_', '_done_(', ')_handle_', '_scenario_as_well')
```
Because it can be any number of open-close brackets, so I am looking for a dynamic regex, but so far I am not able to find anything on it.

regex python-3

Communities

Review Suggested Edit