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How to use grep to print only specific word from a string

~~I have a variable that contains a string-~~
~~`$CCSR = "branches/features/arm_and_musl"`~~
~~I want to pass only the part after the last `/` , in this case its "arm_and_musl" but it can be anything.~~
~~So something like -~~
~~`def dirname= sh " echo $CCSR | grep ????? "`~~
~~But the main issue is that it can be anything it is "branches/features" this time, though it will always be in this format, with only two forward slashes.~~
I'm not sure what to put here so that only the part I want is passed to the variable.
Could you please suggest any solutions for this?

I have a variable that contains a string:
```bash
$CCSR = "branches/features/arm_and_musl"
```
I want to get only the part after the last `/`. In this case it's "arm_and_musl" but it can be anything.
So something like:
```bash
def dirname= sh " echo $CCSR | grep ????? "
```
But the main issue is that it can be anything. It is "branches/features" this time, though it will always be in this format, with only two forward slashes.
I'm not sure what to put here so that only the part I want is passed to the variable.
Could you please suggest any solutions for this?

jenkins shell devops groovy

bash shell

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