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Comments on How to load two or more files in one AJAX call?

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How to load two or more files in one AJAX call?

+0
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In my browser's JavaScript console I can add to the <body> element one file (index.html) with the following AJAX code:

const whereToLoad = document.querySelector("body");
const ajax = new XMLHttpRequest();
ajax.open("GET", "/index.html", false);
ajax.send();
whereToLoad.innerHTML += ajax.responseText;

I tried to change ajax.open to load two files instead, but that failed:

ajax.open(
"GET",
"/index.html", 
"image.svg", 
false
);
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1 comment thread

`open` accepts only one URL. You'll probably have to add a callback after the first request is finish... (3 comments)
`open` accepts only one URL. You'll probably have to add a callback after the first request is finish...
hkotsubo‭ wrote over 2 years ago · edited over 2 years ago

open accepts only one URL. You'll probably have to add a callback after the first request is finished:

ajax.onload = function () {
    // Request finished, make another AJAX call here
    var anotherAjax = new XMLHttpRequest();
    // anotherAjax.open, send, etc...
};
ajax.send();

And, for multiple URL's, you'll have to create another callback for anotherAjax.onload, and then another callback inside it, and so on (welcome to callback hell).

Or you can use fetch API with Promise.all (as the last example here).

That said, what exactly do you need to do? Maybe there's a better solution...

deleted user wrote over 2 years ago · edited over 2 years ago

Thanks hkotsubo‭ what I am ought to do is to load a certain module of three files (patterned as structure.html, style.css and image.svg) into the DOM of each webpage in my website.

I seek a JS solution is because I prefer not to touch the PHP template files of my content management system.

deleted user wrote over 2 years ago

While I should load the first file into the DOM, that's not what I should do with the other two files (they should be loaded from within the appended HTML but it doesn't happen for some reason I should try to isolate and take care of).