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Comments on How to write a macro that discards the const qualifier, for any type?
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How to write a macro that discards the const qualifier, for any type?
How to write a macro that discards the const qualifier, for any type?
I hope some combination of typeof and a cast will do, but haven't found the combination.
I tried this, without luck:
#define discard_const(_x) ((typeof(_x + 0)) (_x))
struct t {
char *s;
};
char *
foo(const struct t *r)
{
return discard_const(r->s);
}
I also tried: #define discard_const(_x) ({__auto_type _y = (_x); _y;}), but not luck
The objective is that if I cast to (char *), I fear that if the type of s changes in the future, the cast might silence any warnings, so I want the type to be automatically calculated, and I only want to discard const.
Of course, with pragmas I may disable any const warnings for that specific line, but a macro that does it within the language would be nicer.
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