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Comments on Postgres command-line variable substitution error

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Postgres command-line variable substitution error

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According to the psql (version 14) man page, it's possible to set variables using the -v command-line parameter, then use the variable in a query, automatically quoted correctly, with :'variable_name'. When issuing SQL commands with -c, this works:

$ psql -v foo=bar -c "\echo :foo"
bar

...and this works:

$ psql -v foo=bar -c "\echo :'foo'"
'bar'

...but this fails:

$ psql -v foo=bar -c "SELECT :'foo' AS foo"
ERROR:  syntax error at or near ":"
LINE 1: SELECT :'foo' AS foo
               ^

Why doesn't the latter syntax work? How can I get a variable substitution via SQL interpolation from the command line?

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I don't know the "real" answer, but from bash on Linux at least, it's possible to work around the issue by using -f instead of -c, using process substitution to supply the SQL:

$ psql -v foo=bar -f <(echo "SELECT :'foo' AS foo;")
 foo 
-----
 bar
(1 row)
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If that works, I would expect a here string to also work: ``` $ psql -v foo=bar -f <<<"SELECT :'f... (2 comments)
If that works, I would expect a here string to also work: ``` $ psql -v foo=bar -f <<<"SELECT :'f...
tripleee‭ wrote over 1 year ago

If that works, I would expect a here string to also work:

$ psql -v foo=bar -f <<<"SELECT :'foo' AS foo;"

... but I don't have a psql instance to quickly test with.

The here string syntax is Bash-only, though I hear it's slated to be included in POSIX eventually.

Andrew‭ wrote over 1 year ago

The here string does work!