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Comments on Slicing a dictionary using a string variable

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Slicing a dictionary using a string variable

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I am working on adding uncertainty to some of my dynamics within a larger Monte Carlo simulation. As a way to perform multiple operations on each value, I decided to make and use a new function to pull from multiple libraries.

Before, I was using something like the following to get the data from the dictionary:

aircraft = 'C172'
dynamicmodel = getattr(ModelLibrary, re.sub(r'[0-9]','',aircraft))
CL0 = dynamicmodel["SCD"]["CL0"]

Now, I am wanting to add a function to this call so that ["SCD"]["CL0"] is the input to the function for example. However, I can't find a way to use this string to slice the dictionary for the correct value.

I have tried using something like the following for the function without success:

aircraft = 'C172'
uncertainty = 'Study1'

dynamicmodel = getattr(ModelLibrary, re.sub(r'[0-9]','',aircraft))
uncertainlibrary = getattr(modeluncertaintylibrary, uncertainty)

value = '["SCD"]["CL0"]'

def generate_val(dynamicmodel, uncertaintylibrary, value):
    CL0 = dynamicmodel + value
    uncertainty_CL0 = uncertaintylibrary + value
    new_CL0 = np.random.uniform((1-uncertainty_CL0)*CL0, (1+uncertainty_CL0)*CL0)
    return new_CL0

However, the data types do not agree and changing the data type does not help, so I am thinking there is probably some work around that I don't know about.

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2 comment threads

Suggestion: Just say the interface (1 comment)
Clarifications and possible syntax error (2 comments)
Suggestion: Just say the interface
matthewsnyder‭ wrote 10 months ago

The question is a bit confusing because the requirement is not clearly stated and the code examples are complex and hard to follow. Can you edit the question and say what arguments exactly the function should take, and what it is expected to return? We can then provide an implementation.