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Is there any guarantee regarding initialization of static and thread_local objects? In example, is there any guarantee about the value printed by the following program? #include<iostream> s...
#3: Post edited
by
Alexei
·
2020-11-19T20:07:23Z (over 3 years ago)
added relevant tags
- Is there any guarantee regarding initialization of static and thread_local objects? In example, is there any guarantee about the value printed by the following program?
- #include<iostream>
- static int a=3;
thread_local int b=a;- int main(void) {
- std::cout << b << std::endl;
- }
- For threads other than the 1st one surely thread_local objects will be initialized after statics(*). But does the C++ standard provide any guarantee that thread_local objects will be initialized after static objects for the 1st thread?
(*) Unless the thread is started from the constructor of a global/static object. But not going there.
- Is there any guarantee regarding initialization of static and thread_local objects? In example, is there any guarantee about the value printed by the following program?
- #include<iostream>
- static int a=3;
- []() int b=a;
- int main(void) {
- std::cout << b << std::endl;
- }
- For threads other than the 1st one surely thread_local objects will be initialized after statics(*). But does the C++ standard provide any guarantee that thread_local objects will be initialized after static objects for the 1st thread?
- (*) Unless the thread is started from the constructor of a global/static object. But not going there.
#2: Post edited
by
Estela
·
2020-11-17T09:45:46Z (over 3 years ago)
- Is there any guarantee regarding initialization of static and thread_local objects? In example, is there any guarantee about the value printed by the following program?
- #include<iostream>
- static int a=3;
- thread_local int b=a;
- int main(void) {
- std::cout << b << std::endl;
- }
- For threads other than the 1st one surely thread_local objects will be initialized after statics(*). But does the C++ standard provide any guarantee that thread_local objects will be initialized after static objects for the 1st thread?
(*) Unless the thread is started from the constructor of an static object. But not going there.
- Is there any guarantee regarding initialization of static and thread_local objects? In example, is there any guarantee about the value printed by the following program?
- #include<iostream>
- static int a=3;
- thread_local int b=a;
- int main(void) {
- std::cout << b << std::endl;
- }
- For threads other than the 1st one surely thread_local objects will be initialized after statics(*). But does the C++ standard provide any guarantee that thread_local objects will be initialized after static objects for the 1st thread?
- (*) Unless the thread is started from the constructor of a global/static object. But not going there.
#1: Initial revision
by
Estela
·
2020-11-17T07:02:47Z (over 3 years ago)
Static and thread_local initialization order
Is there any guarantee regarding initialization of static and thread_local objects? In example, is there any guarantee about the value printed by the following program?
#include<iostream>
static int a=3;
thread_local int b=a;
int main(void) {
std::cout << b << std::endl;
}
For threads other than the 1st one surely thread_local objects will be initialized after statics(*). But does the C++ standard provide any guarantee that thread_local objects will be initialized after static objects for the 1st thread?
(*) Unless the thread is started from the constructor of an static object. But not going there.