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It is possible to create a new formatter class by subclassing string.Formatter class and then to use it like myformatter.format("{foo:customformat}", foo=foo). It's not super-convenient though, and...
#2: Post edited
by
Alexei
·
2021-01-01T11:50:15Z (almost 4 years ago)
added relevant tag
- It is possible to create a new formatter class by subclassing `string.Formatter` class and then to use it like `myformatter.format("{foo:customformat}", foo=foo)`. It's not super-convenient though, and above all, it fails miserably with f-strings, i.e. `f"{foo:customformat}"` won't use my custom formatter class.
I also tried to subclass `str` and override the `.format()` method, but it still won't cut for f-strings.
- It is possible to create a new formatter class by subclassing `string.Formatter` class and then to use it like `myformatter.format("{foo:customformat}", foo=foo)`. It's not super-convenient though, and above all, it fails miserably with f-strings, i.e. `f"{foo:customformat}"` won't use my custom formatter class.
- I also tried to subclass `str` and override the `.format()` method, but it still won't cut for f-strings.
#1: Initial revision
by
luser
·
2020-12-30T20:46:29Z (almost 4 years ago)
How to override default string formatter?
It is possible to create a new formatter class by subclassing `string.Formatter` class and then to use it like `myformatter.format("{foo:customformat}", foo=foo)`. It's not super-convenient though, and above all, it fails miserably with f-strings, i.e. `f"{foo:customformat}"` won't use my custom formatter class.
I also tried to subclass `str` and override the `.format()` method, but it still won't cut for f-strings.