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Is uint8_t guaranteed to be a character type if it exists? Will using a uint8_t* to examine bytes of an object cause violation of the strict aliasing rule? Is the following legal code: #include &l...
#3: Post edited
by
Lundin
·
2021-03-05T09:43:58Z (over 3 years ago)
Added some tags that suit the question
#2: Post edited
by
Ayxan Haqverdili
·
2021-03-04T12:21:21Z (over 3 years ago)
- Is `uint8_t` guaranteed to be a character type if it exists? Will using a `uint8_t*` to examine bytes of an object cause violation of the strict aliasing rule? Is the following legal code:
- ```
- #include <cstdint>
- #include <cstdio>
- #include <string>
- int main() {
- std::string str{"Hello"};
- std::uint8_t* p = reinterpret_cast<std::uint8_t*>(&str);
for (int i = 0; i < sizeof str; ++i) {- std::printf("%d\n", *p++);
- }
- }
- ```
- Is `uint8_t` guaranteed to be a character type if it exists? Will using a `uint8_t*` to examine bytes of an object cause violation of the strict aliasing rule? Is the following legal code:
- ```
- #include <cstddef>
- #include <cstdint>
- #include <cstdio>
- #include <string>
- int main() {
- std::string str{"Hello"};
- std::uint8_t* p = reinterpret_cast<std::uint8_t*>(&str);
- for (std::size_t i = 0; i < sizeof str; ++i) {
- std::printf("%d\n", *p++);
- }
- }
- ```
#1: Initial revision
by
Ayxan Haqverdili
·
2021-03-04T12:19:25Z (over 3 years ago)
Is `uint8_t` always an alias for a character type if it exists?
Is `uint8_t` guaranteed to be a character type if it exists? Will using a `uint8_t*` to examine bytes of an object cause violation of the strict aliasing rule? Is the following legal code:
```
#include <cstdint>
#include <cstdio>
#include <string>
int main() {
std::string str{"Hello"};
std::uint8_t* p = reinterpret_cast<std::uint8_t*>(&str);
for (int i = 0; i < sizeof str; ++i) {
std::printf("%d\n", *p++);
}
}
```