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Q&A Dye all label asterisks Red with vanilla JavaScript

I want to dye all label asterisks Red with vanilla JavaScript. CSS isn't good for this because it would dye both asterisks and colons (:) instead just the asterisks: .labelWithColonAndAsterisk:af...

2 answers · posted 3y ago by deleted user · edited 2y ago by deleted user

Question javascript html validation contact-form accessibility

#3: Post edited by (deleted user) · 2021-11-14T04:09:15Z (over 2 years ago)

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I want to dye all label asterisks Red with vanilla JavaScript.
CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
```css
.labelWithColonAndAsterisk:after {
content:":*";
color:red;
}
```
So, I need a (vanilla) JavaScript solution.
Here is what I have already tried and failed:
```js
const labelsWithAnAsterisk = document.querySelectorAll("label");
labelsWithAnAsterisk.forEach((element) => {
if (element.textContent.indexOf("*") !== -1) {
element.textContent.indexOf("*").style.color = "Red";
}
});
```
> Uncaught TypeError: document.qeurySelectorAll is not a function
at <anonymous>:1:39
~~I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.~~
~~**Anyway, how would you achieve that goal?**~~

I want to dye all label asterisks Red with vanilla JavaScript.
CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
```css
.labelWithColonAndAsterisk:after {
content:":*";
color:red;
}
```
So, I need a (vanilla) JavaScript solution.
Here is what I have already tried and failed:
```js
const labelsWithAnAsterisk = document.querySelectorAll("label");
labelsWithAnAsterisk.forEach((element) => {
if (element.textContent.indexOf("*") !== -1) {
element.textContent.indexOf("*").style.color = "Red";
}
});
```
> Uncaught TypeError: document.qeurySelectorAll is not a function
at <anonymous>:1:39
**How would you achieve that goal?**

#2: Post edited by (deleted user) · 2021-11-14T04:04:55Z (over 2 years ago)

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I want to dye all label asterisks Red with vanilla JavaScript.
CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
```css
.labelWithColonAndAsterisk:after {
content:":*";
color:red;
}
```
So, I need a (vanilla) JavaScript solution.
Here is what I have already tried and failed:
```js
~~const labelsWithAnAsterisk = document.qeurySelectorAll("label");~~
labelsWithAnAsterisk.forEach((element) => {
if (element.textContent.indexOf("*") !== -1) {
element.textContent.indexOf("*").style.color = "Red";
}
});
```
> Uncaught TypeError: document.qeurySelectorAll is not a function
at <anonymous>:1:39
I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.
**Anyway, how would you achieve that goal?**

I want to dye all label asterisks Red with vanilla JavaScript.
CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
```css
.labelWithColonAndAsterisk:after {
content:":*";
color:red;
}
```
So, I need a (vanilla) JavaScript solution.
Here is what I have already tried and failed:
```js
const labelsWithAnAsterisk = document.querySelectorAll("label");
labelsWithAnAsterisk.forEach((element) => {
if (element.textContent.indexOf("*") !== -1) {
element.textContent.indexOf("*").style.color = "Red";
}
});
```
> Uncaught TypeError: document.qeurySelectorAll is not a function
at <anonymous>:1:39
I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.
**Anyway, how would you achieve that goal?**

#1: Initial revision by (deleted user) · 2021-03-21T08:37:11Z (about 3 years ago)

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Dye all label asterisks Red with vanilla JavaScript

I want to dye all label asterisks Red with vanilla JavaScript.

CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:

```css
.labelWithColonAndAsterisk:after {
    content:":*"; 
    color:red;
}
```

So, I need a (vanilla) JavaScript solution.

Here is what I have already tried and failed:

```js
const labelsWithAnAsterisk = document.qeurySelectorAll("label");
labelsWithAnAsterisk.forEach((element) => {
    if (element.textContent.indexOf("*") !== -1) {
        element.textContent.indexOf("*").style.color = "Red";
    }
});
```

> Uncaught TypeError: document.qeurySelectorAll is not a function
    at <anonymous>:1:39

I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.

**Anyway, how would you achieve that goal?**

javascript html validation contact-form accessibility

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