Communities

Writing
Writing
Codidact Meta
Codidact Meta
The Great Outdoors
The Great Outdoors
Photography & Video
Photography & Video
Scientific Speculation
Scientific Speculation
Cooking
Cooking
Electrical Engineering
Electrical Engineering
Judaism
Judaism
Languages & Linguistics
Languages & Linguistics
Software Development
Software Development
Mathematics
Mathematics
Christianity
Christianity
Code Golf
Code Golf
Music
Music
Physics
Physics
Linux Systems
Linux Systems
Power Users
Power Users
Tabletop RPGs
Tabletop RPGs
Community Proposals
Community Proposals
tag:snake search within a tag
answers:0 unanswered questions
user:xxxx search by author id
score:0.5 posts with 0.5+ score
"snake oil" exact phrase
votes:4 posts with 4+ votes
created:<1w created < 1 week ago
post_type:xxxx type of post
Search help
Notifications
Mark all as read See all your notifications »
Q&A

Welcome to Software Development on Codidact!

Will you help us build our independent community of developers helping developers? We're small and trying to grow. We welcome questions about all aspects of software development, from design to code to QA and more. Got questions? Got answers? Got code you'd like someone to review? Please join us.

Post History

66%
+4 −1
Q&A Dye all label asterisks Red with vanilla JavaScript

I want to dye all label asterisks Red with vanilla JavaScript. CSS isn't good for this because it would dye both asterisks and colons (:) instead just the asterisks: .labelWithColonAndAsterisk:af...

2 answers  ·  posted 3y ago by deleted user  ·  edited 3y ago by deleted user

#3: Post edited by (deleted user) · 2021-11-14T04:09:15Z (about 3 years ago)
  • I want to dye all label asterisks Red with vanilla JavaScript.
  • CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
  • ```css
  • .labelWithColonAndAsterisk:after {
  • content:":*";
  • color:red;
  • }
  • ```
  • So, I need a (vanilla) JavaScript solution.
  • Here is what I have already tried and failed:
  • ```js
  • const labelsWithAnAsterisk = document.querySelectorAll("label");
  • labelsWithAnAsterisk.forEach((element) => {
  • if (element.textContent.indexOf("*") !== -1) {
  • element.textContent.indexOf("*").style.color = "Red";
  • }
  • });
  • ```
  • > Uncaught TypeError: document.qeurySelectorAll is not a function
  • at <anonymous>:1:39
  • I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.
  • **Anyway, how would you achieve that goal?**
  • I want to dye all label asterisks Red with vanilla JavaScript.
  • CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
  • ```css
  • .labelWithColonAndAsterisk:after {
  • content:":*";
  • color:red;
  • }
  • ```
  • So, I need a (vanilla) JavaScript solution.
  • Here is what I have already tried and failed:
  • ```js
  • const labelsWithAnAsterisk = document.querySelectorAll("label");
  • labelsWithAnAsterisk.forEach((element) => {
  • if (element.textContent.indexOf("*") !== -1) {
  • element.textContent.indexOf("*").style.color = "Red";
  • }
  • });
  • ```
  • > Uncaught TypeError: document.qeurySelectorAll is not a function
  • at <anonymous>:1:39
  • **How would you achieve that goal?**
#2: Post edited by (deleted user) · 2021-11-14T04:04:55Z (about 3 years ago)
  • I want to dye all label asterisks Red with vanilla JavaScript.
  • CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
  • ```css
  • .labelWithColonAndAsterisk:after {
  • content:":*";
  • color:red;
  • }
  • ```
  • So, I need a (vanilla) JavaScript solution.
  • Here is what I have already tried and failed:
  • ```js
  • const labelsWithAnAsterisk = document.qeurySelectorAll("label");
  • labelsWithAnAsterisk.forEach((element) => {
  • if (element.textContent.indexOf("*") !== -1) {
  • element.textContent.indexOf("*").style.color = "Red";
  • }
  • });
  • ```
  • > Uncaught TypeError: document.qeurySelectorAll is not a function
  • at <anonymous>:1:39
  • I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.
  • **Anyway, how would you achieve that goal?**
  • I want to dye all label asterisks Red with vanilla JavaScript.
  • CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:
  • ```css
  • .labelWithColonAndAsterisk:after {
  • content:":*";
  • color:red;
  • }
  • ```
  • So, I need a (vanilla) JavaScript solution.
  • Here is what I have already tried and failed:
  • ```js
  • const labelsWithAnAsterisk = document.querySelectorAll("label");
  • labelsWithAnAsterisk.forEach((element) => {
  • if (element.textContent.indexOf("*") !== -1) {
  • element.textContent.indexOf("*").style.color = "Red";
  • }
  • });
  • ```
  • > Uncaught TypeError: document.qeurySelectorAll is not a function
  • at <anonymous>:1:39
  • I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.
  • **Anyway, how would you achieve that goal?**
#1: Initial revision by (deleted user) · 2021-03-21T08:37:11Z (over 3 years ago)
Dye all label asterisks Red with vanilla JavaScript
I want to dye all label asterisks Red with vanilla JavaScript.

CSS isn't good for this because it would dye both asterisks and colons (`:`) instead just the asterisks:

```css
.labelWithColonAndAsterisk:after {
    content:":*"; 
    color:red;
}
```

So, I need a (vanilla) JavaScript solution.

Here is what I have already tried and failed:

```js
const labelsWithAnAsterisk = document.qeurySelectorAll("label");
labelsWithAnAsterisk.forEach((element) => {
    if (element.textContent.indexOf("*") !== -1) {
        element.textContent.indexOf("*").style.color = "Red";
    }
});
```

> Uncaught TypeError: document.qeurySelectorAll is not a function
    at <anonymous>:1:39

I understand that one element can't have two color properties (black for colon and red for asterisk) and this might explain the error.

**Anyway, how would you achieve that goal?**