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Q&A How to read lines into an array in Bash

I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried: declare -a my_array=() while read line; do my_array+=( "$line"...

3 answers · posted 3y ago by LVx0‭ · edited 3y ago by Alexei‭

Question array bash console stdin

#7: Post edited by

Alexei‭ · 2021-09-01T04:53:06Z (about 3 years ago)
added relevant tag

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array bash stdin

array bash console stdin

#6: Post edited by

Alexei‭ · 2021-08-27T06:48:54Z (about 3 years ago)
added relevant tag

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array bash

array bash stdin

#5: Post edited by

Quasímodo‭ · 2021-08-18T12:41:34Z (over 3 years ago)
Move this important comment here to the question.

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How to read lines into an array in Bash

I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
```
declare -a my_array=()
while read line; do
my_array+=( "$line" )
done < my_file.txt
```
~~But it seems to only add the first line.~~

I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
```
declare -a my_array=()
while read line; do
my_array+=( "$line" )
done < my_file.txt
```
But it seems to only add the first line as tested with `echo "$my_array"`.

array bash

#4: Post edited by

Alexei‭ · 2021-03-23T06:35:44Z (over 3 years ago)
added relevant tag

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bash

array bash

#3: Post edited by

LVx0‭ · 2021-03-22T14:52:34Z (over 3 years ago)
figured out how to make a code block

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I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
~~`declare -a my_array=()`~~
`
while read line; do
my_array+=( "$line" )
~~done < my_file.txt`~~
But it seems to only add the first line.

I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
```
declare -a my_array=()
while read line; do
my_array+=( "$line" )
done < my_file.txt
```
But it seems to only add the first line.

#2: Post edited by

LVx0‭ · 2021-03-22T14:49:37Z (over 3 years ago)
trying to create a code block

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I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
`
~~declare -a my_array=()~~
while read line; do
my_array+=( "$line" )
~~done < my_file.txt~~
`
But it seems to only add the first line.

I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
`declare -a my_array=()`
`
while read line; do
my_array+=( "$line" )
done < my_file.txt`
But it seems to only add the first line.

#1: Initial revision by

LVx0‭ · 2021-03-22T14:47:06Z (over 3 years ago)

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How to read lines into an array in Bash

I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:


 `
declare -a my_array=()

while read line; do
    my_array+=( "$line" )
done < my_file.txt
`

But it seems to only add the first line.

bash

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