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Q&A How to read lines into an array in Bash

I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried: declare -a my_array=() while read line; do my_array+=( "$line"...

3 answers  ·  posted 3y ago by LVx0‭  ·  edited 3y ago by Alexei‭

Question array bash console stdin
#7: Post edited by user avatar Alexei‭ · 2021-09-01T04:53:06Z (about 3 years ago)
added relevant tag
#6: Post edited by user avatar Alexei‭ · 2021-08-27T06:48:54Z (about 3 years ago)
added relevant tag
#5: Post edited by user avatar Quasímodo‭ · 2021-08-18T12:41:34Z (about 3 years ago)
Move this important comment here to the question.
How to read lines into an array in Bash
  • I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
  • ```
  • declare -a my_array=()
  • while read line; do
  • my_array+=( "$line" )
  • done < my_file.txt
  • ```
  • But it seems to only add the first line.
  • I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
  • ```
  • declare -a my_array=()
  • while read line; do
  • my_array+=( "$line" )
  • done < my_file.txt
  • ```
  • But it seems to only add the first line as tested with `echo "$my_array"`.
#4: Post edited by user avatar Alexei‭ · 2021-03-23T06:35:44Z (over 3 years ago)
added relevant tag
#3: Post edited by user avatar LVx0‭ · 2021-03-22T14:52:34Z (over 3 years ago)
figured out how to make a code block
  • I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
  • `declare -a my_array=()`
  • `
  • while read line; do
  • my_array+=( "$line" )
  • done < my_file.txt`
  • But it seems to only add the first line.
  • I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
  • ```
  • declare -a my_array=()
  • while read line; do
  • my_array+=( "$line" )
  • done < my_file.txt
  • ```
  • But it seems to only add the first line.
#2: Post edited by user avatar LVx0‭ · 2021-03-22T14:49:37Z (over 3 years ago)
trying to create a code block
  • I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
  • `
  • declare -a my_array=()
  • while read line; do
  • my_array+=( "$line" )
  • done < my_file.txt
  • `
  • But it seems to only add the first line.
  • I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:
  • `declare -a my_array=()`
  • `
  • while read line; do
  • my_array+=( "$line" )
  • done < my_file.txt`
  • But it seems to only add the first line.
#1: Initial revision by user avatar LVx0‭ · 2021-03-22T14:47:06Z (over 3 years ago)
How to read lines into an array in Bash
I wish to fill an array with strings, using Bash scripting. The strings are in a file, one per line. Here is what I've tried:


 `
declare -a my_array=()

while read line; do
    my_array+=( "$line" )
done < my_file.txt
`

But it seems to only add the first line.