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updating a function within a struct
What I want: An object that contains a function that I can update after creation.
I created a struct that contains a parameter b and a function(closure?) named Internal_Fn.
struct MyThing {
b: f32,
Internal_Fn: Box<dyn Fn(f32) -> f32>,
}
To allow me to update Internal_Fn, I add the update_Fn method to MyThing.
impl MyThing {
fn update_Fn(&mut self, delta_b: f32) {
let new_b = self.b + delta_b;
self.b = new_b;
self.Internal_Fn = Box::new(|x: f32| ((1.0 + new_b).powf(x) - 1.0) / new_b);
}
}
I get a compiler error
9 | self.Internal_Fn = Box::new(|x: f32| ((1.0 + new_b).powf(x) - 1.0) / new_b);
| --------------------------^^^^^-------------------------
| | | |
| | | borrowed value does not live long enough
| | value captured here
| cast requires that `new_b` is borrowed for `'static`
10 | }
| - `new_b` dropped here while still borrowed
If I understand correctly, the problem is that the parameter that I set in my new Internal_Fn (i.e. new_b) is dropped once the update_Fn is finished but Internal_Fn is supposed to live on.
Is that correct?
How do I do this? I don't just want to hard code the shape of the function and only update the parameter b. I want to be able to also provide entirely differently shaped functions.
1 answer
You are correct in your analysis (though I would not call new_b a "parameter" but a captured variable).
What you want is for the closure (anonymous function) to take responsibility for new_b and not just borrow it temporarily. In other words, you want move semantics and not a borrow.
As mentioned in Rust by Example, closures borrow their captured variables by default. If you would instead like to move them, you simply need to put move before the parameter list of the closure. (See the bottom of the linked section.) That is:
impl MyThing {
fn update_Fn(&mut self, delta_b: f32) {
let new_b = self.b + delta_b;
self.b = new_b;
self.Internal_Fn = Box::new(move |x: f32| ((1.0 + new_b).powf(x) - 1.0) / new_b);
}
}
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