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#include <iostream> using namespace std; int linearSearch(int array[], int n, int key){ for(int i=0;i<=n;i++){ if(array[i]==key){ return i; } } } int main() { int ...
#4: Post edited
by
Anonymous
·
2021-08-31T06:22:09Z (about 3 years ago)
What might happen if I ignore the return-type warning?
- What might happen if I ignore warning?
- ```c++
- #include <iostream>
- using namespace std;
- int linearSearch(int array[], int n, int key){
- for(int i=0;i<=n;i++){
- if(array[i]==key){
- return i;
- }
- }
- }
- int main() {
- int balance[] = {10,240,120,150,100};
- cout<<linearSearch(balance, sizeof(balance)/sizeof(balance[0]), 150);
- return 0;
- }
- ```
- When executing the code I got an warning. Should I really care of warning? I got expected output. Although, I was thinking of warning. What might happen if I ignore warning?
- ```c++
- test.cpp: In function ‘int linearSearch(int*, int, int)’:
- test.cpp:10:1: warning: control reaches end of non-void function [-Wreturn-type]
- 10 | }
- | ^
- ```
When I add `return 0;` at end of for loop I don't get the error anymore. The warning was saying that the `linearSearch` method (function) wasn't [returning](https://stackoverflow.com/questions/22742581/warning-control-reaches-end-of-non-void-function-wreturn-type#22742601) always. But, can warning crash my applications?
- ```c++
- #include <iostream>
- using namespace std;
- int linearSearch(int array[], int n, int key){
- for(int i=0;i<=n;i++){
- if(array[i]==key){
- return i;
- }
- }
- }
- int main() {
- int balance[] = {10,240,120,150,100};
- cout<<linearSearch(balance, sizeof(balance)/sizeof(balance[0]), 150);
- return 0;
- }
- ```
- When executing the code I got an warning. Should I really care of warning? I got expected output. Although, I was thinking of warning. What might happen if I ignore warning?
- ```c++
- test.cpp: In function ‘int linearSearch(int*, int, int)’:
- test.cpp:10:1: warning: control reaches end of non-void function [-Wreturn-type]
- 10 | }
- | ^
- ```
- When I add `return 0;` at end of for loop I don't get the error anymore. The warning was saying that the `linearSearch` method (function) wasn't [returning](https://stackoverflow.com/questions/22742581/warning-control-reaches-end-of-non-void-function-wreturn-type#22742601) always. But, can warning crash my applications?
- **Replying to last edit of Alexei** : My question was about any type of warning not only above one. Above one was just an example. Anyway, I got more accurate answer in [the thread](https://software.codidact.com/comments/thread/4280)
#3: Post edited
by
Alexei
·
2021-08-30T16:48:59Z (about 3 years ago)
added relevant tag + simplified the title
Should I really care of warning? What might happen if I ignore warning?
- What might happen if I ignore the return-type warning?
#2: Post edited
by
Anonymous
·
2021-08-30T16:31:15Z (about 3 years ago)
- ```c++
- #include <iostream>
- using namespace std;
- int linearSearch(int array[], int n, int key){
- for(int i=0;i<=n;i++){
- if(array[i]==key){
- return i;
- }
- }
- }
- int main() {
- int balance[] = {10,240,120,150,100};
- cout<<linearSearch(balance, sizeof(balance)/sizeof(balance[0]), 150);
- return 0;
- }
- ```
- When executing the code I got an warning. Should I really care of warning? I got expected output. Although, I was thinking of warning. What might happen if I ignore warning?
- ```c++
- test.cpp: In function ‘int linearSearch(int*, int, int)’:
- test.cpp:10:1: warning: control reaches end of non-void function [-Wreturn-type]
- 10 | }
- | ^
```
- ```c++
- #include <iostream>
- using namespace std;
- int linearSearch(int array[], int n, int key){
- for(int i=0;i<=n;i++){
- if(array[i]==key){
- return i;
- }
- }
- }
- int main() {
- int balance[] = {10,240,120,150,100};
- cout<<linearSearch(balance, sizeof(balance)/sizeof(balance[0]), 150);
- return 0;
- }
- ```
- When executing the code I got an warning. Should I really care of warning? I got expected output. Although, I was thinking of warning. What might happen if I ignore warning?
- ```c++
- test.cpp: In function ‘int linearSearch(int*, int, int)’:
- test.cpp:10:1: warning: control reaches end of non-void function [-Wreturn-type]
- 10 | }
- | ^
- ```
- When I add `return 0;` at end of for loop I don't get the error anymore. The warning was saying that the `linearSearch` method (function) wasn't [returning](https://stackoverflow.com/questions/22742581/warning-control-reaches-end-of-non-void-function-wreturn-type#22742601) always. But, can warning crash my applications?
#1: Initial revision
by
Anonymous
·
2021-08-30T16:28:03Z (about 3 years ago)
Should I really care of warning? What might happen if I ignore warning?
```c++
#include <iostream>
using namespace std;
int linearSearch(int array[], int n, int key){
for(int i=0;i<=n;i++){
if(array[i]==key){
return i;
}
}
}
int main() {
int balance[] = {10,240,120,150,100};
cout<<linearSearch(balance, sizeof(balance)/sizeof(balance[0]), 150);
return 0;
}
```
When executing the code I got an warning. Should I really care of warning? I got expected output. Although, I was thinking of warning. What might happen if I ignore warning?
```c++
test.cpp: In function ‘int linearSearch(int*, int, int)’:
test.cpp:10:1: warning: control reaches end of non-void function [-Wreturn-type]
10 | }
| ^
```