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Q&A How allocated memory is calculated?

The size of the "primitive data types" int, float etc is not defined by the standard. In practice, int is either 16 or 32 bits on all known systems. Because of the unspecified size leading to poor...

posted 2y ago by Lundin‭  ·  edited 2y ago by Canina‭

Answer
#2: Post edited by user avatar Canina‭ · 2021-08-31T14:36:12Z (over 2 years ago)
  • The size of the "privite data types" int, float etc is not defined by the standard. In practice, int is either 16 or 32 bits on all known systems.
  • Because of the unspecified size leading to poor portability of the primitive types, the stdint.h library was introduced back in 1999, containing fixed width types that are portable. `uint32_t` etc. These are the preferred types in professional settings where portability matters.
  • In your specific case, if we assume a 32 bit system then each int is 4 bytes. The array is then 4x6 = 24 bytes large.
  • The size of the "primitive data types" int, float etc is not defined by the standard. In practice, int is either 16 or 32 bits on all known systems.
  • Because of the unspecified size leading to poor portability of the primitive types, the stdint.h library was introduced back in 1999, containing fixed width types that are portable. `uint32_t` etc. These are the preferred types in professional settings where portability matters.
  • In your specific case, if we assume a 32 bit system then each int is 4 bytes. The array is then 4x6 = 24 bytes large.
#1: Initial revision by user avatar Lundin‭ · 2021-08-31T10:05:03Z (over 2 years ago)
The size of the "privite data types" int, float etc is not defined by the standard. In practice, int is either 16 or 32 bits on all known systems.

Because of the unspecified size leading to poor portability of the primitive types, the stdint.h library was introduced back in 1999, containing fixed width types that are portable. `uint32_t` etc. These are the preferred types in professional settings where portability matters.

In your specific case, if we assume a 32 bit system then each int is 4 bytes. The array is then 4x6 = 24 bytes large.