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I have a list of 11-digit numbers stored in one single column in Excel, and I need to separate the digits according to this pattern: 2-2-1-3-3. Example: 00002451018 becomes 00 00 2 451 018. How c...
#3: Post edited
- I have a list of 11-digit numbers stored in one single column in Excel, and I need to separate the digits according to this pattern: `2-2-1-3-3`.
- Example: `00002451018` becomes `00 00 2 451 018`.
How can I do it in Python?
- I have a list of 11-digit numbers stored in one single column in Excel, and I need to separate the digits according to this pattern: `2-2-1-3-3`.
- Example: `00002451018` becomes `00 00 2 451 018`.
- How can I do it in Python?
- I have tried the following:
- ![Python implementation](https://software.codidact.com/uploads/1CxdEXsPMXCqH8HGU9aPAJLF)
- If you notice the last column new Value is getting only from the last row. Which is ending with 416. Somehow I want inside of this to update and create a new column to contain for each row the updated pattern.
#2: Post edited
Transform number in specific pattern in Python
- Separate digits of a number in groups with different sizes
I have a list of numbers stored in one single column in Excel.<br>All numbers are 11 digit length.<br>For example 00002451018 I need to transform it in this specific pattern 00 00 2 451 018.<br>The pattern is 2-2-1-3-3.<br>How can I do it in Python?<br><br>Thanks in advance!
- I have a list of 11-digit numbers stored in one single column in Excel, and I need to separate the digits according to this pattern: `2-2-1-3-3`.
- Example: `00002451018` becomes `00 00 2 451 018`.
- How can I do it in Python?
#1: Initial revision
Transform number in specific pattern in Python
I have a list of numbers stored in one single column in Excel.<br> All numbers are 11 digit length.<br> For example 00002451018 I need to transform it in this specific pattern 00 00 2 451 018.<br> The pattern is 2-2-1-3-3.<br> How can I do it in Python?<br> <br> Thanks in advance!