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I found a way how to fix it after I debug. It was only using the last used row because there was nothing to check that I want to edit only the current row. That's why I decide to use at for index,...
Answer
#4: Post edited
by
Alexei
·
2021-11-09T06:05:33Z (about 3 years ago)
removed the additional question from the answer
Hi, I have one more question, because I do something wrong. If you notice the last column new Value is getting only from the last row. Which is ending with 416. Somehow I want inside of this for to update and create the new column to contain for each row the updated pattern.**[EDIT]**I found a way how to fix it after I debug. It was only using the last used row, because there was nothing to check that I want to edit only the current row. That's why I decide to use `at`- ```Python
- for index, row in priceListTest.iterrows():
- #print(index,row)
- def get_slices(n, sizes, n_digits=11):
- for size in sizes:
- n_digits -= size
- val, n = divmod(n, 10 ** n_digits)
- yield f'{val:0{size}}'
- n = row['Парт номер']
- newVar = (' '.join(get_slices(n, [2, 2, 1, 3, 3])))
- priceListTest.at[index,['New Value']] = newVar
- print("after changes")
- print(priceListTest)
- I found a way how to fix it after I debug. It was only using the last used row because there was nothing to check that I want to edit only the current row. That's why I decide to use `at`
- ```Python
- for index, row in priceListTest.iterrows():
- #print(index,row)
- def get_slices(n, sizes, n_digits=11):
- for size in sizes:
- n_digits -= size
- val, n = divmod(n, 10 ** n_digits)
- yield f'{val:0{size}}'
- n = row['Парт номер']
- newVar = (' '.join(get_slices(n, [2, 2, 1, 3, 3])))
- priceListTest.at[index,['New Value']] = newVar
- print("after changes")
- print(priceListTest)
#3: Post edited
by
sfrow
·
2021-11-08T19:16:23Z (about 3 years ago)
- Hi, I have one more question, because I do something wrong. If you notice the last column new Value is getting only from the last row. Which is ending with 416. Somehow I want inside of this for to update and create the new column to contain for each row the updated pattern.
- 
- I found a way how to fix it after I debug. It was only using the last used row, because there was nothing to check that I want to edit only the current row. That's why I decide to use `at`
- ```Python
- for index, row in priceListTest.iterrows():
- #print(index,row)
- def get_slices(n, sizes, n_digits=11):
- for size in sizes:
- n_digits -= size
- val, n = divmod(n, 10 ** n_digits)
- yield f'{val:0{size}}'
- n = row['Парт номер']
- newVar = (' '.join(get_slices(n, [2, 2, 1, 3, 3])))
- priceListTest.at[index,['New Value']] = newVar
- print("after changes")
- print(priceListTest)
- Hi, I have one more question, because I do something wrong. If you notice the last column new Value is getting only from the last row. Which is ending with 416. Somehow I want inside of this for to update and create the new column to contain for each row the updated pattern.
- 
- **[EDIT]**
- I found a way how to fix it after I debug. It was only using the last used row, because there was nothing to check that I want to edit only the current row. That's why I decide to use `at`
- ```Python
- for index, row in priceListTest.iterrows():
- #print(index,row)
- def get_slices(n, sizes, n_digits=11):
- for size in sizes:
- n_digits -= size
- val, n = divmod(n, 10 ** n_digits)
- yield f'{val:0{size}}'
- n = row['Парт номер']
- newVar = (' '.join(get_slices(n, [2, 2, 1, 3, 3])))
- priceListTest.at[index,['New Value']] = newVar
- print("after changes")
- print(priceListTest)
#2: Post edited
by
sfrow
·
2021-11-08T19:15:26Z (about 3 years ago)
- Hi, I have one more question, because I do something wrong. If you notice the last column new Value is getting only from the last row. Which is ending with 416. Somehow I want inside of this for to update and create the new column to contain for each row the updated pattern.
- Hi, I have one more question, because I do something wrong. If you notice the last column new Value is getting only from the last row. Which is ending with 416. Somehow I want inside of this for to update and create the new column to contain for each row the updated pattern.
- 
- I found a way how to fix it after I debug. It was only using the last used row, because there was nothing to check that I want to edit only the current row. That's why I decide to use `at`
- ```Python
- for index, row in priceListTest.iterrows():
- #print(index,row)
- def get_slices(n, sizes, n_digits=11):
- for size in sizes:
- n_digits -= size
- val, n = divmod(n, 10 ** n_digits)
- yield f'{val:0{size}}'
- n = row['Парт номер']
- newVar = (' '.join(get_slices(n, [2, 2, 1, 3, 3])))
- priceListTest.at[index,['New Value']] = newVar
- print("after changes")
- print(priceListTest)
#1: Initial revision
by
sfrow
·
2021-11-08T18:21:54Z (about 3 years ago)
Hi, I have one more question, because I do something wrong. If you notice the last column new Value is getting only from the last row. Which is ending with 416. Somehow I want inside of this for to update and create the new column to contain for each row the updated pattern. 