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Q&A Behavior of Pointer Arithmetic on the Stack

This is absolutely undefined behavior. The C standard doesn't say anything about stacks or how they should behave or how local variables should be allocated on them. The word "stack" doesn't even ...

posted 3y ago by Derek Elkins‭

Answer
#1: Initial revision by user avatar Derek Elkins‭ · 2021-12-14T02:05:00Z (almost 3 years ago)
This is absolutely undefined behavior.

The C standard doesn't say anything about stacks or how they should behave or how local variables should be allocated on them. The word "stack" doesn't even occur in the C standard^[Feel free to do a string search on [this working draft version of the 2018 C standard](https://web.archive.org/web/20181230041359if_/http://www.open-std.org/jtc1/sc22/wg14/www/abq/c17_updated_proposed_fdis.pdf).].

C does say that (for arrays) that it is only valid to index one past the end of them, e.g. given `int x[2]`, `x+2` is a valid pointer but it is undefined behavior to dereference that pointer. If we view `&b` as a array of length 1, then you would be invoking undefined behavior when you dereference `&b+1`.

Ultimately, there is absolutely nothing that states how the locations of two separate variables are related to each other in memory. This isn't surprising as a variable doesn't need to even be allocated in memory. It would be a completely valid and not uncommon optimization for the compiler to register allocate the variable `a` or even just completely eliminate it by constant propagation/folding. In that case, your code would most likely be mutating something like a return address or a stack frame pointer which will almost certainly lead to a crash and/or erratic behavior.