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Q&A Is it OK to use scanf with a void pointer?

From section 7.21.6.2 of this draft: [T]he result of the conversion is placed in the object pointed to by the first argument following the format argument that has not already received a conve...

posted 2y ago by r~~‭

Answer
#1: Initial revision by user avatar r~~‭ · 2022-02-16T20:43:07Z (about 2 years ago)
From section 7.21.6.2 of [this draft](http://www.open-std.org/jtc1/sc22/wg14/www/docs/n2310.pdf):

> [T]he result of the conversion is placed in the object
pointed to by the first argument following the `format` argument that has not already received a
conversion result. If this object does not have an appropriate type, or if the result of the conversion
cannot be represented in the object, the behavior is undefined.

So per the spec, it is the type of the *object*, not the *pointer* to the object, that must match the format specifier. A compiler that doesn't interpret the quoted code to have the behavior you saw would on this point not be spec-compliant.