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I managed to do it with lambda. Something like this: Set<U> ulist = new LinkedHashSet<>(); @Test void test() { doAnswer(i -> { U arg = i.getArgument(0); ...
Answer
#3: Post edited
by
klutt
·
2022-03-07T12:39:21Z (over 2 years ago)
- I managed to do it with lambda. Something like this:
List<U> ulist = new ArrayList<>();- @Test
- void test() {
- doAnswer(i -> {
- U arg = i.getArgument(0);
- if(ulist.contains(arg)) {
- return 0;
- }
- ulist.add(arg);
- return 1;
- }).when(b).add(any());
- I managed to do it with lambda. Something like this:
- Set<U> ulist = new LinkedHashSet<>();
- @Test
- void test() {
- doAnswer(i -> {
- U arg = i.getArgument(0);
- if(ulist.contains(arg)) {
- return 0;
- }
- ulist.add(arg);
- return 1;
- }).when(b).add(any());
#2: Post edited
by
klutt
·
2022-03-07T12:35:58Z (over 2 years ago)
- I managed to do it with lambda. Something like this:
- List<U> ulist = new ArrayList<>();
- @Test
- void test() {
- doAnswer(i -> {
T arg = i.getArgument(0);- if(ulist.contains(arg)) {
- return 0;
- }
- ulist.add(arg);
- return 1;
- }).when(b).add(any());
- I managed to do it with lambda. Something like this:
- List<U> ulist = new ArrayList<>();
- @Test
- void test() {
- doAnswer(i -> {
- U arg = i.getArgument(0);
- if(ulist.contains(arg)) {
- return 0;
- }
- ulist.add(arg);
- return 1;
- }).when(b).add(any());
#1: Initial revision
by
klutt
·
2022-02-28T11:55:07Z (over 2 years ago)
I managed to do it with lambda. Something like this:
List<U> ulist = new ArrayList<>();
@Test
void test() {
doAnswer(i -> {
T arg = i.getArgument(0);
if(ulist.contains(arg)) {
return 0;
}
ulist.add(arg);
return 1;
}).when(b).add(any());