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C++ exit code -1073740940 [closed]
Closed as unclear by Alexei on Mar 22, 2022 at 13:42
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2 answers
Nothing.
Or anything.
Or whatever you want it to mean.
As a general rule of thumb:
- If you explicitly exit from a program with a specific exit status, then you know the meaning, or set of meanings, of that exit status value. This knowledge will inform your answer.
- If you don't exit from a program with a specific exit status, then the exit status is set by something else.
In the latter case, the "something else" can be anything.
The exit status could be an error code; or it could be an intermediary result of some operation that failed; or it could be some kind of garbage value that just happened to be in the location used to hold an exit status when the program terminated; or something entirely different that I can't even think of.
We can't possibly know.
If the result is reproducible, even if the specific value changes, then use a debugger to determine what causes the program to exit unexpectedly, and work your way from there.
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C++ doesn't have error codes/exit codes other than return 0; / EXIT_SUCCESS / EXIT_FAILURE. The code you are getting is from the OS when your program crashes from a run-time error.
-1073740940 is unhelpful gibberish, you need to convert this from 2's complement 32 bit into hex. Then you get C0000374 which is Windows' exception code for heap corruption.
Meaning you have some pointer or array related bug in your program. Manual management of new/delete gone wrong would be the first thing to look for.
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