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I misunderstand why the following code outputs -1 in console. x = 42; x = (x == 42) * -1 + (x != 42) * x; -1 Due to Type Coercion, the comparison of x to 42 yields true and is thus transl...
#4: Post edited
by
Alexei
·
2022-05-01T17:11:46Z (over 2 years ago)
Replaced the title to match what is actually being asked
Type coercion with both true and false in JavaScript
- Explaining the result of an arithmetic expression in JavaScript
#3: Post edited
by
Dirk Herrmann
·
2022-05-01T14:47:51Z (over 2 years ago)
The question is about operator precendence rather than type coercion. I was thinking also about changing the title in this direction...
Type coercion with both true and false in JavaScript
I misunderstand why the following code outputs -1 in console. ```javascript x = 42; x = (x == 42) * -1 + (x != 42) * x; ``` > -1 Due to [Type Coercion](https://developer.mozilla.org/en-US/docs/Glossary/Type_coercion), the comparison of x to 42 yields `true` and is thus translated to `1`. So `1 * -1` yields `-1`. Now, `(x != 42)` which is `false` yields `0` so I have expected to get in console > -42 Because `-1 + 0 * 42 MEANS -42`. So why did I get `-1` in the end?
#2: Post edited
- I misunderstand why the following code outputs -1 in console.
- ```javascript
- x = 42;
- x = (x == 42) * -1 + (x != 42) * x;
- ```
- > -1
- Due to [Type Coercion](https://developer.mozilla.org/en-US/docs/Glossary/Type_coercion), the comparison of x to 42 yields `true` and is thus translated to `1`.
- So `1 * -1` yields `-1`.
Now, to `(x != 42)` which is `false` yields `0` so I have expected to get in console- > -42
- Because `-1 + 0 * 42 MEANS -42`.
- So why did I get `-1` in the end?
- I misunderstand why the following code outputs -1 in console.
- ```javascript
- x = 42;
- x = (x == 42) * -1 + (x != 42) * x;
- ```
- > -1
- Due to [Type Coercion](https://developer.mozilla.org/en-US/docs/Glossary/Type_coercion), the comparison of x to 42 yields `true` and is thus translated to `1`.
- So `1 * -1` yields `-1`.
- Now, `(x != 42)` which is `false` yields `0` so I have expected to get in console
- > -42
- Because `-1 + 0 * 42 MEANS -42`.
- So why did I get `-1` in the end?
#1: Initial revision
Type coercion with both true and false in JavaScript
I misunderstand why the following code outputs -1 in console. ```javascript x = 42; x = (x == 42) * -1 + (x != 42) * x; ``` > -1 Due to [Type Coercion](https://developer.mozilla.org/en-US/docs/Glossary/Type_coercion), the comparison of x to 42 yields `true` and is thus translated to `1`. So `1 * -1` yields `-1`. Now, to `(x != 42)` which is `false` yields `0` so I have expected to get in console > -42 Because `-1 + 0 * 42 MEANS -42`. So why did I get `-1` in the end?