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Q&A How to use grep to print only specific word from a string

I have a variable that contains a string: $CCSR = "branches/features/arm_and_musl" I want to get only the part after the last /. In this case it's "arm_and_musl" but it can be anything. So som...

3 answers  ·  posted 2y ago by Megan‭  ·  edited 2y ago by hkotsubo‭

Question bash shell
#3: Nominated for promotion by user avatar Alexei‭ · 2022-07-24T10:47:44Z (over 2 years ago)
#2: Post edited by user avatar hkotsubo‭ · 2022-07-22T01:05:42Z (over 2 years ago)
formatting, minor fixes, remove unrelated tags
How to use grep to print only specific word from a string
  • I have a variable that contains a string-
  • `$CCSR = "branches/features/arm_and_musl"`
  • I want to pass only the part after the last `/` , in this case its "arm_and_musl" but it can be anything.
  • So something like -
  • `def dirname= sh " echo $CCSR | grep ????? "`
  • But the main issue is that it can be anything it is "branches/features" this time, though it will always be in this format, with only two forward slashes.
  • I'm not sure what to put here so that only the part I want is passed to the variable.
  • Could you please suggest any solutions for this?
  • I have a variable that contains a string:
  • ```bash
  • $CCSR = "branches/features/arm_and_musl"
  • ```
  • I want to get only the part after the last `/`. In this case it's "arm_and_musl" but it can be anything.
  • So something like:
  • ```bash
  • def dirname= sh " echo $CCSR | grep ????? "
  • ```
  • But the main issue is that it can be anything. It is "branches/features" this time, though it will always be in this format, with only two forward slashes.
  • I'm not sure what to put here so that only the part I want is passed to the variable.
  • Could you please suggest any solutions for this?
#1: Initial revision by user avatar Megan‭ · 2022-07-20T21:26:07Z (over 2 years ago)
How to use grep to print only specific word from a string
I have a variable that contains a string-

`$CCSR = "branches/features/arm_and_musl"`

I want to pass only the part after the last `/` , in this case its "arm_and_musl" but it can be anything. 

So something like -

`def dirname= sh " echo $CCSR | grep ????? "`

But the main issue is that it can be anything it is "branches/features" this time, though it will always be in this format, with only two forward slashes.

I'm not sure what to put here so that only the part I want is passed to the variable.

Could you please suggest any solutions for this?