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I am trying to define a syntax word as follows: USING: kernel syntax parser fry prettyprint ; IN: syn-try SYNTAX: syn scan-word '[ _ ] . ; Given a word, I want to create a quotation conta...
#4: Post edited
by
Alexei
·
2022-08-17T05:09:38Z (over 2 years ago)
added relevant tag
#3: Post edited
by
Alexei
·
2022-08-17T05:08:10Z (over 2 years ago)
clarified what programming language we are dealing with
How to create a quotation containing the given token in a syntax word
- How to create a quotation containing the given token in a syntax word in Factor programming language
#2: Post edited
by
Razetime
·
2022-08-16T12:08:15Z (over 2 years ago)
fix scan-word
- I am trying to define a syntax word as follows:
- ```
- USING: kernel syntax parser fry prettyprint ;
- IN: syn-try
SYNTAX: syn scan-token '[ _ ] . ;- ```
- Given a word, I want to create a quotation containing the word.
- In the factor listener, if i do `syn word` I get `[ \ word ]`. How do I remove the `\`?
- Language version is Factor 0.98 for Linux.
- I am trying to define a syntax word as follows:
- ```
- USING: kernel syntax parser fry prettyprint ;
- IN: syn-try
- SYNTAX: syn scan-word '[ _ ] . ;
- ```
- Given a word, I want to create a quotation containing the word.
- In the factor listener, if i do `syn word` I get `[ \ word ]`. How do I remove the `\`?
- Language version is Factor 0.98 for Linux.
#1: Initial revision
by
Razetime
·
2022-08-16T11:48:31Z (over 2 years ago)
How to create a quotation containing the given token in a syntax word
I am trying to define a syntax word as follows: ``` USING: kernel syntax parser fry prettyprint ; IN: syn-try SYNTAX: syn scan-token '[ _ ] . ; ``` Given a word, I want to create a quotation containing the word. In the factor listener, if i do `syn word` I get `[ \ word ]`. How do I remove the `\`? Language version is Factor 0.98 for Linux.