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The answer for this question is that there is something wrong with the expression of the first guard of this function below: congratulations :: [(String, Int)] -> [String] congratulations [] =...
Question
haskell
#3: Question closed
by
Alexei
·
2022-11-28T06:24:46Z (almost 2 years ago)
#2: Post edited
by
Anonymous
·
2022-11-27T21:26:58Z (almost 2 years ago)
- The answer for this question is that there is something wrong with the expression of the first guard of this function below:
- ```
- congratulations :: [(String, Int)] -> [String]
- congratulations [] = []
- congratulations ((name,mark):rest)
- | mark > 40 = name
- | otherwise = congratulations rest
- ```
What should be the correct expression for the first guard of the function?
- The answer for this question is that there is something wrong with the expression of the first guard of this function below:
- ```
- congratulations :: [(String, Int)] -> [String]
- congratulations [] = []
- congratulations ((name,mark):rest)
- | mark > 40 = name
- | otherwise = congratulations rest
- ```
- What should be the correct expression for the first guard of the function and why?
#1: Initial revision
by
Anonymous
·
2022-11-27T21:26:39Z (almost 2 years ago)
Haskell revision question.
The answer for this question is that there is something wrong with the expression of the first guard of this function below: ``` congratulations :: [(String, Int)] -> [String] congratulations [] = [] congratulations ((name,mark):rest) | mark > 40 = name | otherwise = congratulations rest ``` What should be the correct expression for the first guard of the function?