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Q&A What's causing mypy to give an `[assignment]` error in this nested for loop?

The problem is that you are using row twice with different types. for row in self.diagram: # row is str here for row in self.seed_diagram: # row is list[str] here Renaming one or the other m...

posted 1y ago by Moshi‭  ·  edited 1y ago by Moshi‭

Answer
#2: Post edited by user avatar Moshi‭ · 2022-12-28T01:38:08Z (over 1 year ago)
Python's initialization-is-declaration philosophy makes this wording a bit confusing
  • The problem is that you are declaring `row` twice.
  • ```py
  • for row in self.diagram: # row is str here
  • ```
  • ```py
  • for row in self.seed_diagram: # row is list[str] here
  • ```
  • Renaming one or the other makes the error go away.
  • Why does this happen? Python has some somewhat counterintuitive odd scoping rules. Take the following example:
  • ```py
  • def foo():
  • l = [["hello"], ["world"]]
  • for x in l:
  • for y in x:
  • pass
  • print(y)
  • foo()
  • ```
  • The `foo` call actually prints `world`! In Python, loops (and other conditionals) do not create a new block scope, and so in fact both `row` variables in your code are one and the same, scoped to the function, and so mypy gets upset when you try to use it with different types.
  • The problem is that you are using `row` twice with different types.
  • ```py
  • for row in self.diagram: # row is str here
  • ```
  • ```py
  • for row in self.seed_diagram: # row is list[str] here
  • ```
  • Renaming one or the other makes the error go away.
  • Why does this happen? Python has some somewhat counterintuitive scoping rules. Take the following example:
  • ```py
  • def foo():
  • l = [["hello"], ["world"]]
  • for x in l:
  • for y in x:
  • pass
  • print(y)
  • foo()
  • ```
  • The `foo` call actually prints `world`! In Python, loops (and other conditionals) do not create a new block scope, and so in fact both `row` variables in your code are one and the same, scoped to the function, and so mypy gets upset when you try to use it with different types.
#1: Initial revision by user avatar Moshi‭ · 2022-12-28T01:34:51Z (over 1 year ago)
The problem is that you are declaring `row` twice.

```py
for row in self.diagram: # row is str here
```

```py
for row in self.seed_diagram: # row is list[str] here
```

Renaming one or the other makes the error go away.

Why does this happen? Python has some somewhat counterintuitive odd scoping rules. Take the following example:

```py
def foo():
    l = [["hello"], ["world"]]
    for x in l:
        for y in x:
            pass
    print(y)

foo()
```

The `foo` call actually prints `world`! In Python, loops (and other conditionals) do not create a new block scope, and so in fact both `row` variables in your code are one and the same, scoped to the function, and so mypy gets upset when you try to use it with different types.