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Q&A Python Parallel plotting and and input reading

Hello everyone, I am seeking help with understanding why multithreading does not work correctly in this example: import time import matplotlib.pyplot as plt import concurrent.futures voltage...

1 answer  ·  posted 2y ago by kek‭  ·  edited 2y ago by kek‭

#4: Nominated for promotion by user avatar Alexei‭ · 2023-02-04T06:36:01Z (almost 2 years ago)
#3: Post edited by user avatar kek‭ · 2023-02-03T21:17:29Z (almost 2 years ago)
fixed the code in the 2nd snippet to working condition
  • Hello everyone,
  • I am seeking help with understanding why multithreading does not work correctly in this example:
  • ```python
  • import time
  • import matplotlib.pyplot as plt
  • import concurrent.futures
  • voltage = list()
  • stop_flag = False
  • fig, ax = plt.subplots()
  • fig.show()
  • def plotter(ax, arr):
  • while True:
  • if stop_flag:
  • print("stream interupted")
  • return
  • arr.append(1)
  • ax.clear()
  • ax.plot(arr)
  • ax.get_figure().canvas.draw()
  • ax.get_figure().canvas.flush_events()
  • time.sleep(1)
  • with concurrent.futures.ThreadPoolExecutor() as executor:
  • plot_thread = executor.submit(plotter, ax, voltage)
  • for _ in range(15):
  • res = input("Type: ")
  • if res == "q":
  • stop_flag = True
  • break
  • print(res)
  • ```
  • **Expected behaviour:**
  • Graph is being spawned by matplotlib and the line at `y=1` is continuously growing in the x direction. In parallel terminal waits for user input. If input is `q`, the function plotter exits and everything finishes.
  • **Actual behaviour:**
  • Graph is appearing, but not updating at all, while user input is being processed and reprinted to console. It seems that one point does exist on the graph. When pressing q or reaching 15 iterations program terminates.
  • I do not understand why parallel thread does not run and updates the graph independently from `for` loop.
  • **Edit:**
  • Changing plotting to the main program and running input loop in another thread also does not work:
  • ```python
  • import time
  • import matplotlib.pyplot as plt
  • import concurrent.futures
  • import matplotlib
  • matplotlib.use("tkAgg") # lock tk backend
  • voltage = list()
  • stop_flag = False
  • fig, ax = plt.subplots()
  • fig.show()
  • def fetch_input():
  • for _ in range(15):
  • res = input("Type: ")
  • if res == "q":
  • stop_flag = True
  • break
  • print(res)
  • with concurrent.futures.ThreadPoolExecutor() as executor:
  • new_thread = executor.submit(fetch_input)
  • while True:
  • if stop_flag:
  • print("main loop interupted")
  • break
  • voltage.append(1)
  • ax.clear()
  • ax.plot(voltage)
  • ax.get_figure().canvas.draw()
  • ax.get_figure().canvas.flush_events()
  • plt.pause(1) # run eventloop for 1 second
  • # time.sleep(1)
  • ```
  • First the function fetching the input starts and continues until it finished and only then the figure appears. It is even weirder now, since `fig.show()` happens in the beginning before the thread is even started. So I would expect to see at least empty figure together with input query in the terminal.
  • Hello everyone,
  • I am seeking help with understanding why multithreading does not work correctly in this example:
  • ```python
  • import time
  • import matplotlib.pyplot as plt
  • import concurrent.futures
  • voltage = list()
  • stop_flag = False
  • fig, ax = plt.subplots()
  • fig.show()
  • def plotter(ax, arr):
  • while True:
  • if stop_flag:
  • print("stream interupted")
  • return
  • arr.append(1)
  • ax.clear()
  • ax.plot(arr)
  • ax.get_figure().canvas.draw()
  • ax.get_figure().canvas.flush_events()
  • time.sleep(1)
  • with concurrent.futures.ThreadPoolExecutor() as executor:
  • plot_thread = executor.submit(plotter, ax, voltage)
  • for _ in range(15):
  • res = input("Type: ")
  • if res == "q":
  • stop_flag = True
  • break
  • print(res)
  • ```
  • **Expected behaviour:**
  • Graph is being spawned by matplotlib and the line at `y=1` is continuously growing in the x direction. In parallel terminal waits for user input. If input is `q`, the function plotter exits and everything finishes.
  • **Actual behaviour:**
  • Graph is appearing, but not updating at all, while user input is being processed and reprinted to console. It seems that one point does exist on the graph. When pressing q or reaching 15 iterations program terminates.
  • I do not understand why parallel thread does not run and updates the graph independently from `for` loop.
  • **Edit:**
  • Changing plotting to the main program and running input loop in another thread also does not work:
  • ```python
  • import time
  • import matplotlib.pyplot as plt
  • import concurrent.futures
  • import matplotlib
  • matplotlib.use("tkAgg") # lock tk backend
  • voltage = list()
  • stop_flag = False
  • fig, ax = plt.subplots()
  • fig.show()
  • def fetch_input():
  • global stop_flag
  • for _ in range(15):
  • res = input("Type: ")
  • if res == "q":
  • stop_flag = True
  • break
  • print(res)
  • with concurrent.futures.ThreadPoolExecutor() as executor:
  • new_thread = executor.submit(fetch_input)
  • while True:
  • if stop_flag:
  • print("main loop interupted")
  • break
  • voltage.append(1)
  • ax.clear()
  • ax.plot(voltage)
  • ax.get_figure().canvas.draw()
  • ax.get_figure().canvas.flush_events()
  • plt.pause(1) # run eventloop for 1 second
  • # time.sleep(1)
  • ```
  • First the function fetching the input starts and continues until it finished and only then the figure appears. It is even weirder now, since `fig.show()` happens in the beginning before the thread is even started. So I would expect to see at least empty figure together with input query in the terminal.
#2: Post edited by user avatar kek‭ · 2023-02-03T17:44:26Z (almost 2 years ago)
  • Hello everyone,
  • I am seeking help with understanding why multithreading does not work correctly in this example:
  • ```python
  • import time
  • import matplotlib.pyplot as plt
  • import concurrent.futures
  • voltage = list()
  • stop_flag = False
  • fig, ax = plt.subplots()
  • fig.show()
  • def plotter(ax, arr):
  • while True:
  • if stop_flag:
  • print("stream interupted")
  • return
  • arr.append(1)
  • ax.clear()
  • ax.plot(arr)
  • ax.get_figure().canvas.draw()
  • ax.get_figure().canvas.flush_events()
  • time.sleep(1)
  • with concurrent.futures.ThreadPoolExecutor() as executor:
  • plot_thread = executor.submit(plotter, ax, voltage)
  • for _ in range(15):
  • res = input("Type: ")
  • if res == "q":
  • stop_flag = True
  • break
  • print(res)
  • ```
  • **Expected behaviour:**
  • Graph is being spawned by matplotlib and the line at `y=1` is continuously growing in the x direction. In parallel terminal waits for user input. If input is `q`, the function plotter exits and everything finishes.
  • **Actual behaviour:**
  • Graph is appearing, but not updating at all, while user input is being processed and reprinted to console. It seems that one point does exist on the graph. When pressing q or reaching 15 iterations program terminates.
  • I do not understand why parallel thread does not run and updates the graph independently from `for` loop.
  • Hello everyone,
  • I am seeking help with understanding why multithreading does not work correctly in this example:
  • ```python
  • import time
  • import matplotlib.pyplot as plt
  • import concurrent.futures
  • voltage = list()
  • stop_flag = False
  • fig, ax = plt.subplots()
  • fig.show()
  • def plotter(ax, arr):
  • while True:
  • if stop_flag:
  • print("stream interupted")
  • return
  • arr.append(1)
  • ax.clear()
  • ax.plot(arr)
  • ax.get_figure().canvas.draw()
  • ax.get_figure().canvas.flush_events()
  • time.sleep(1)
  • with concurrent.futures.ThreadPoolExecutor() as executor:
  • plot_thread = executor.submit(plotter, ax, voltage)
  • for _ in range(15):
  • res = input("Type: ")
  • if res == "q":
  • stop_flag = True
  • break
  • print(res)
  • ```
  • **Expected behaviour:**
  • Graph is being spawned by matplotlib and the line at `y=1` is continuously growing in the x direction. In parallel terminal waits for user input. If input is `q`, the function plotter exits and everything finishes.
  • **Actual behaviour:**
  • Graph is appearing, but not updating at all, while user input is being processed and reprinted to console. It seems that one point does exist on the graph. When pressing q or reaching 15 iterations program terminates.
  • I do not understand why parallel thread does not run and updates the graph independently from `for` loop.
  • **Edit:**
  • Changing plotting to the main program and running input loop in another thread also does not work:
  • ```python
  • import time
  • import matplotlib.pyplot as plt
  • import concurrent.futures
  • import matplotlib
  • matplotlib.use("tkAgg") # lock tk backend
  • voltage = list()
  • stop_flag = False
  • fig, ax = plt.subplots()
  • fig.show()
  • def fetch_input():
  • for _ in range(15):
  • res = input("Type: ")
  • if res == "q":
  • stop_flag = True
  • break
  • print(res)
  • with concurrent.futures.ThreadPoolExecutor() as executor:
  • new_thread = executor.submit(fetch_input)
  • while True:
  • if stop_flag:
  • print("main loop interupted")
  • break
  • voltage.append(1)
  • ax.clear()
  • ax.plot(voltage)
  • ax.get_figure().canvas.draw()
  • ax.get_figure().canvas.flush_events()
  • plt.pause(1) # run eventloop for 1 second
  • # time.sleep(1)
  • ```
  • First the function fetching the input starts and continues until it finished and only then the figure appears. It is even weirder now, since `fig.show()` happens in the beginning before the thread is even started. So I would expect to see at least empty figure together with input query in the terminal.
#1: Initial revision by user avatar kek‭ · 2023-02-03T12:03:45Z (almost 2 years ago)
Python Parallel plotting and and input reading
Hello everyone,

I am seeking help with understanding why multithreading does not work correctly in this example:

```python
import time
import matplotlib.pyplot as plt
import concurrent.futures

voltage = list()
stop_flag = False
fig, ax = plt.subplots()
fig.show()

def plotter(ax, arr):
    while True:
        if stop_flag:
            print("stream interupted")
            return
        arr.append(1)
        ax.clear()
        ax.plot(arr)
        ax.get_figure().canvas.draw()
        ax.get_figure().canvas.flush_events()
        time.sleep(1)

with concurrent.futures.ThreadPoolExecutor() as executor:
    plot_thread = executor.submit(plotter, ax, voltage)

for _ in range(15):
    res = input("Type: ")
    if res == "q":
        stop_flag = True
        break
    print(res)
```

**Expected behaviour:**
Graph is being spawned by matplotlib and the line at `y=1` is continuously growing in the x direction. In parallel terminal waits for user input. If input is `q`, the function plotter exits and everything finishes.

**Actual behaviour:**
Graph is appearing, but not updating at all, while user input is being processed and reprinted to console. It seems that one point does exist on the graph. When pressing q or reaching 15 iterations program terminates.


I do not understand why parallel thread does not run and updates the graph independently from `for` loop.