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Q&A What are statements and expressions?

To add to the excellent explanation by FractionalRadix, it's worth mentioning that sometimes the line between expressions and statements can seem a little blurry (at least to the observer — the lan...

posted 1y ago by deleted user  ·  edited 1y ago by deleted user

Answer
#2: Post edited by (deleted user) · 2023-08-04T11:23:40Z (over 1 year ago)
Add Python example
  • To add to the excellent explanation by FractionalRadix, it's worth mentioning that sometimes the line between expressions and statements can seem a little blurry (at least to the observer — the language specification will almost certainly define the boundaries clearly and precisely).
  • For example, in C we have the expression `++i`, which means "add one to the value of `i` and return the new value". This is an expression because it yields a value, but it also makes a change to the program state. Therefore you can use it as a "pure" expression and assign it to something else:
  • int iNew = ++i; // increment i, put incremented value into iNew
  • or you can use it as a statement in its own right:
  • ++i; // increment i and do nothing else
  • Also in C, a simple assignment can be an expression as well as a statement, e.g.
  • int x = 2; // statement
  • int y = (x = 3); // y and x are now both equal to 3
  • Informally, you can think of an expression as something you **can** (but don't necessarily **have to**) put on the right-hand side of an assignment operation.
  • Languages may also different in which constructs they treat as statements or expressions. In Rust, an `if` construct is actually an expression, not a statement, and can be assigned as a value:
  • let x = if (y == 2) { 5 } else { 10 };
  • If you try this in C you'll get a compilation error because `if` is a statement and does not evaluate to a value:
  • int x = if (y == 2) { 5; } else { 10; } // INVALID; won't compile
  • To add to the excellent explanation by FractionalRadix, it's worth mentioning that sometimes the line between expressions and statements can seem a little blurry (at least to the observer — the language specification will almost certainly define the boundaries clearly and precisely).
  • For example, in C we have the expression `++i`, which means "add one to the value of `i` and return the new value". This is an expression because it yields a value, but it also makes a change to the program state. Therefore you can use it as a "pure" expression and assign it to something else:
  • int iNew = ++i; // increment i, put incremented value into iNew
  • or you can use it as a statement in its own right:
  • ++i; // increment i and do nothing else
  • Also in C, a simple assignment can be an expression as well as a statement, e.g.
  • int x = 2; // statement
  • int y = (x = 3); // y and x are now both equal to 3
  • Informally, you can think of an expression as something you **can** (but don't necessarily **have to**) put on the right-hand side of an assignment operation.
  • Languages may also differ in which constructs they treat as statements or expressions. In Rust, an `if` construct is actually an expression, not a statement, and can be assigned as a value:
  • let x = if (y == 2) { 5 } else { 10 };
  • If you try this in C you'll get a compilation error because `if` is a statement and does not evaluate to a value:
  • int x = if (y == 2) { 5; } else { 10; } // INVALID; won't compile
  • But in Python, you can't treat an assignment as an expression like you can in C, unless you use a special [recently-introduced syntax](https://peps.python.org/pep-0572/):
  • x = 2
  • y = (x = 3)
  • ^
  • SyntaxError: invalid syntax. Maybe you meant '==' or ':=' instead of '='?
  • y = (x := 3) # x and y are now both 3
#1: Initial revision by (deleted user) · 2023-08-04T09:23:39Z (over 1 year ago)
To add to the excellent explanation by FractionalRadix, it's worth mentioning that sometimes the line between expressions and statements can seem a little blurry (at least to the observer — the language specification will almost certainly define the boundaries clearly and precisely).

For example, in C we have the expression `++i`, which means "add one to the value of `i` and return the new value". This is an expression because it yields a value, but it also makes a change to the program state. Therefore you can use it as a "pure" expression and assign it to something else:

    int iNew = ++i; // increment i, put incremented value into iNew

or you can use it as a statement in its own right:

    ++i; // increment i and do nothing else

Also in C, a simple assignment can be an expression as well as a statement, e.g.

    int x = 2; // statement
    int y = (x = 3); // y and x are now both equal to 3

Informally, you can think of an expression as something you **can** (but don't necessarily **have to**) put on the right-hand side of an assignment operation.

Languages may also different in which constructs they treat as statements or expressions. In Rust, an `if` construct is actually an expression, not a statement, and can be assigned as a value:

    let x = if (y == 2) { 5 } else { 10 };

If you try this in C you'll get a compilation error because `if` is a statement and does not evaluate to a value:

    int x = if (y == 2) { 5; } else { 10; } // INVALID; won't compile