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I have the following xarray Dataset: d: <xarray.Dataset> Dimensions: (x: 79, y: 63, t: 1) Coordinates: * x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35 * ...
#3: Post edited
by
Ivan Nepomnyashchikh
·
2023-08-16T15:47:20Z (over 1 year ago)
- I have the following [xarray](https://docs.xarray.dev/en/stable/index.html) `Dataset`:
- ```
- d: <xarray.Dataset>
- Dimensions: (x: 79, y: 63, t: 1)
- Coordinates:
- * x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35
- * y (y) float64 59.29 58.35 57.41 56.47 ... 3.765 2.824 1.882 0.9412
- * t (t) int32 0
- Data variables:
- u (x, y, t) float64 0.0 0.0 0.0 0.0 0.0 0.0 ... 0.0 0.0 0.0 0.0 0.0
- v (x, y, t) float64 -0.0 -0.0 -0.0 -0.0 -0.0 ... -0.0 -0.0 -0.0 -0.0
- chc (x, y, t) float64 1.0 1.0 1.0 1.0 1.0 1.0 ... 1.0 1.0 1.0 1.0 1.0
- Attributes: (2)
- ```
- When I try to assign new values to the coordinate `t`, using `d = d.assign_coords(t = 0.123)`, I receive an error:
- `ValueError: dimension 't' already exists as a scalar variable`
- How can I resolve the error and assign a new value to the `t` coordinate?
- I have tried the solutions to the similar problems posted on Stack Overflow, such as
- * `assign_coords` is not an inplace operation
- * recreate `t` as a coordinate and then assign the value to it
- * change the type of `t` to `float`
- I suspect that the asterisk next to the name of my coordinate `t` has something to do with the error. But I don't understand what it means; I could only find that it is a reference to something called "proper coordinate".
- I have the following [xarray](https://docs.xarray.dev/en/stable/index.html) `Dataset`:
- ```
- d: <xarray.Dataset>
- Dimensions: (x: 79, y: 63, t: 1)
- Coordinates:
- * x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35
- * y (y) float64 59.29 58.35 57.41 56.47 ... 3.765 2.824 1.882 0.9412
- * t (t) int32 0
- Data variables:
- u (x, y, t) float64 0.0 0.0 0.0 0.0 0.0 0.0 ... 0.0 0.0 0.0 0.0 0.0
- v (x, y, t) float64 -0.0 -0.0 -0.0 -0.0 -0.0 ... -0.0 -0.0 -0.0 -0.0
- chc (x, y, t) float64 1.0 1.0 1.0 1.0 1.0 1.0 ... 1.0 1.0 1.0 1.0 1.0
- Attributes: (2)
- ```
- When I try to assign new values to the coordinate `t`, using `d = d.assign_coords(t = 0.123)`, I receive an error:
- `ValueError: dimension 't' already exists as a scalar variable`
- How can I resolve the error and assign a new value to the `t` coordinate?
- I have tried the solutions to the similar problems posted on Stack Overflow, such as
- * `assign_coords` is not an inplace operation
- * recreate `t` as a coordinate and then assign the value to it
- * change the type of `t` to `float`
- * using dictionary: `d = d.assign_coords({'t':0.123})`
- I suspect that the asterisk next to the name of my coordinate `t` has something to do with the error. But I don't understand what it means; I could only find that it is a reference to something called "proper coordinate".
#2: Post edited
by
Karl Knechtel
·
2023-08-16T06:06:04Z (over 1 year ago)
remove noise, fix formatting, add link for lesser-known third-party library, improve grammar
How to resolve a "ValueError: dimension 't' already exists as a scalar variable" arising when I am using xarray.Dataset.assign_coords()?
I have the following `xarray.Dataset`:`d: <xarray.Dataset>``Dimensions: (x: 79, y: 63, t: 1)``Coordinates:``* x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35`` * y (y) float64 59.29 58.35 57.41 56.47 ... 3.765 2.824 1.882 0.9412``* t (t) int32 0``Data variables:`- u (x, y, t) float64 0.0 0.0 0.0 0.0 0.0 0.0 ... 0.0 0.0 0.0 0.0 0.0
- v (x, y, t) float64 -0.0 -0.0 -0.0 -0.0 -0.0 ... -0.0 -0.0 -0.0 -0.0
- chc (x, y, t) float64 1.0 1.0 1.0 1.0 1.0 1.0 ... 1.0 1.0 1.0 1.0 1.0
`Attributes: (2)`I'm trying to assign new values to the coordinate `t` using `.assign_coords()`:`d = d.assign_coords(t = 0.123)`I receive an error: `ValueError: dimension 't' already exists as a scalar variable`How to resolve the error and assign a new value to the `t` coordinate?-------------------I have tried the solutions to the similar problems posted on StackOverflow, such as 1) `assign_coords` is not an inplace operation, 2) recreate `t` as a coordinate and then assign the value to it, 3) change the type of `t` to `float`. Also, I suspected that the asterisk next to the name of my coordinate `t` has something to do with the error. But I don't know what the asterisk means, I could only find that it is a reference to something called "proper coordinate".P.S. I am sorry for the formatting of my code: I didn't know how to code-format a chunk of code spanning several lines.
- I have the following [xarray](https://docs.xarray.dev/en/stable/index.html) `Dataset`:
- ```
- d: <xarray.Dataset>
- Dimensions: (x: 79, y: 63, t: 1)
- Coordinates:
- * x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35
- * y (y) float64 59.29 58.35 57.41 56.47 ... 3.765 2.824 1.882 0.9412
- * t (t) int32 0
- Data variables:
- u (x, y, t) float64 0.0 0.0 0.0 0.0 0.0 0.0 ... 0.0 0.0 0.0 0.0 0.0
- v (x, y, t) float64 -0.0 -0.0 -0.0 -0.0 -0.0 ... -0.0 -0.0 -0.0 -0.0
- chc (x, y, t) float64 1.0 1.0 1.0 1.0 1.0 1.0 ... 1.0 1.0 1.0 1.0 1.0
- Attributes: (2)
- ```
- When I try to assign new values to the coordinate `t`, using `d = d.assign_coords(t = 0.123)`, I receive an error:
- `ValueError: dimension 't' already exists as a scalar variable`
- How can I resolve the error and assign a new value to the `t` coordinate?
- I have tried the solutions to the similar problems posted on Stack Overflow, such as
- * `assign_coords` is not an inplace operation
- * recreate `t` as a coordinate and then assign the value to it
- * change the type of `t` to `float`
- I suspect that the asterisk next to the name of my coordinate `t` has something to do with the error. But I don't understand what it means; I could only find that it is a reference to something called "proper coordinate".
#1: Initial revision
by
Ivan Nepomnyashchikh
·
2023-08-15T21:17:42Z (over 1 year ago)
How to resolve a "ValueError: dimension 't' already exists as a scalar variable" arising when I am using xarray.Dataset.assign_coords()?
I have the following `xarray.Dataset`:
`d: <xarray.Dataset>`
`Dimensions: (x: 79, y: 63, t: 1)`
`Coordinates:`
`* x (x) float64 0.9412 1.882 2.824 3.765 ... 71.53 72.47 73.41 74.35`
` * y (y) float64 59.29 58.35 57.41 56.47 ... 3.765 2.824 1.882 0.9412`
`* t (t) int32 0`
`Data variables:`
u (x, y, t) float64 0.0 0.0 0.0 0.0 0.0 0.0 ... 0.0 0.0 0.0 0.0 0.0
v (x, y, t) float64 -0.0 -0.0 -0.0 -0.0 -0.0 ... -0.0 -0.0 -0.0 -0.0
chc (x, y, t) float64 1.0 1.0 1.0 1.0 1.0 1.0 ... 1.0 1.0 1.0 1.0 1.0
`Attributes: (2)`
I'm trying to assign new values to the coordinate `t` using `.assign_coords()`:
`d = d.assign_coords(t = 0.123)`
I receive an error: `ValueError: dimension 't' already exists as a scalar variable`
How to resolve the error and assign a new value to the `t` coordinate?
-------------------
I have tried the solutions to the similar problems posted on StackOverflow, such as 1) `assign_coords` is not an inplace operation, 2) recreate `t` as a coordinate and then assign the value to it, 3) change the type of `t` to `float`. Also, I suspected that the asterisk next to the name of my coordinate `t` has something to do with the error. But I don't know what the asterisk means, I could only find that it is a reference to something called "proper coordinate".
P.S. I am sorry for the formatting of my code: I didn't know how to code-format a chunk of code spanning several lines.