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Q&A OpenGL: Pass a double vector from vertex shader to fragment shader

Found a workaround: Instead of doing the calculating in the vertex shader, do it in the fragment shader. The precision error only occurs because the different vertexes have a uv value that is clos...

posted 1y ago by H_H‭  ·  edited 1y ago by H_H‭

Answer
#2: Post edited by user avatar H_H‭ · 2023-08-22T17:56:02Z (about 1 year ago)
  • Found a workaround: Instead of doing the calculating in the vertex shader, do it in the fragment shader.
  • The precision error only occurs because the different vertexes have a `uv` value that is close together relative to the absolute value of `uv`. Which causes multiple fragments to have the same `uv` coordinates which causes this artefacts. By passing `uv` directly, with coordinates that only have the values `-1` `1`, each fragment shader instance gets its own `uv` value that is different from the others. The calculation inside the fragment shader can be done with double precision.
  • The good thing is, the main program can pass `double` values, when the correct extensions are supported.
  • The new fragment shader:
  • ```
  • #version 400
  • //Moved zoom from the vertex shader. This is set by the main program.
  • // with glUniformMatrix3dv()
  • uniform dmat3 zoom;
  • //uv values are not transformed.
  • in vec2 uv;
  • ...
  • void main()
  • {
  • dvec2 uv_double = uv;
  • uv_double = ( zoom * dvec3(uv_double,1)).xy ;
  • //us uv_double from here on and not uv
  • ...
  • }
  • ```
  • Disadvantage is that `glUniformMatrix3dv()` has to be supported and a other very minor disadvantage is that this is probably slower.
  • Found a workaround: Instead of doing the calculating in the vertex shader, do it in the fragment shader.
  • The precision error only occurs because the different vertexes have a `uv` value that is close together relative to the absolute value of `uv`. Which causes multiple fragments to have the same `uv` coordinates which causes this artefacts. By passing `uv` directly, with coordinates that only have the values `-1` `1`, each fragment shader instance gets its own `uv` value that is different from the others. The calculation inside the fragment shader can be done with double precision.
  • The good thing is, the main program can pass `double` values, when the correct extensions are supported.
  • The new fragment shader:
  • ```
  • #version 400
  • //Moved zoom from the vertex shader. This is set by the main program.
  • // with glUniformMatrix3dv()
  • uniform dmat3 zoom;
  • //uv values are not transformed.
  • in vec2 uv;
  • ...
  • void main()
  • {
  • dvec2 uv_double = uv;
  • uv_double = ( zoom * dvec3(uv_double,1)).xy ;
  • //us uv_double from here on and not uv
  • ...
  • }
  • ```
  • Disadvantage is that `glUniformMatrix3dv()` is an extension any may not be supported everywhere. A other very minor disadvantage is that this is probably slower.
#1: Initial revision by user avatar H_H‭ · 2023-08-22T17:55:05Z (about 1 year ago)
Found a workaround: Instead of doing the calculating in the vertex shader, do it in the fragment shader.

The precision error only occurs because the different vertexes have a `uv` value that is close together relative to the absolute value of `uv`. Which causes multiple fragments to have the same `uv` coordinates which causes this artefacts. By passing `uv` directly, with coordinates that only have the values `-1` `1`, each fragment shader instance gets its own `uv` value that is different from the others. The calculation inside the fragment shader can be done with double precision.

The good thing is, the main program can pass `double` values, when the correct extensions are supported.

The new fragment shader:
```
#version 400

//Moved zoom from the vertex shader. This is set by the main program.
// with glUniformMatrix3dv()
uniform dmat3 zoom;

//uv values are not transformed.
in vec2 uv;

...

void main()
{
  dvec2 uv_double = uv;
  uv_double = ( zoom * dvec3(uv_double,1)).xy ;
  //us uv_double from here on and not uv
  ...
}
```

Disadvantage is that `glUniformMatrix3dv()` has to be supported and a other very minor disadvantage is that this is probably slower.