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Q&A Pipeline for zipping multiple file chanel into a single output channel

Well, ain't this fun hehe Turns out I failed to see .reader launches its own job, which resulted in multiple coroutines contending for the zip stream, each trying to write an entry... 🤦 The solut...

posted 1y ago by tmpod‭

Answer
#1: Initial revision by user avatar tmpod‭ · 2023-09-12T00:30:55Z (over 1 year ago)
Well, ain't this fun hehe

Turns out I failed to see [`.reader`](https://api.ktor.io/ktor-io/io.ktor.utils.io/reader.html) launches its own job, which resulted in multiple coroutines contending for the zip stream, each trying to write an entry... 🤦

The solution was just to get a channel and use that instead. Additionally, to mitigate the still blocking nature of Java's `ZipOutputStream`, I spawned the job in the appropriate [`Dispatchers.IO`](https://kotlinlang.org/api/kotlinx.coroutines/kotlinx-coroutines-core/kotlinx.coroutines/-dispatchers/-i-o.html).  
Here it is:

```kotlin
ChannelProvider {
    val fileChannel = ByteChannel()
    val zos = ZipOutputStream(fileChannel.toOutputStream())
    coroScope.launch(Dispatchers.IO) {
        files.forEach { f ->
            val body = httpClient.get(f.url).bodyAsChannel()
            zos.putNextEntry(ZipEntry(f.filename))
            while (!body.isClosedForRead) {
                body.readRemaining(DEFAULT_BUFFER_SIZE.toLong()).let {
                    zos.writePacket(it)
                }
            }
            zos.closeEntry()
        }
        zos.close()
        fileChannel.close()
    }
    fileChannel
}
```