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Q&A Why does this work? .collect() automatic conversion to function return type

You're very much on the right track. std::iter::FromIterator trait This trait is indeed what makes it work. In particular, both functions' return types implement the trait: std::result::Result&l...

posted 9mo ago by Iizuki‭

Answer
#1: Initial revision by user avatar Iizuki‭ · 2024-02-21T08:32:29Z (9 months ago)
You're very much on the right track.

# std::iter::FromIterator trait

This trait is indeed what makes it work. In particular, both functions' return types implement the trait:

`std::result::Result<A,E>` implements it if `A` implements it.[^result] And here `A = std::Vec`.


`std::Vec` implements it as long as the iterated type matches the type contained in the Vec.[^vec]


# Turbofish operator

Yes you can force `collect`'s output type with the turbofish operator:

```rust
someIter.collect::<Vec<Result<i32, DivisionError>>()
```

Or you don't have to specify the whole type:

```rust
someIter.collect::<Vec<Result<_>>()
someIter.collect::<Vec<_>()
```

If not on the returning line, you could also use type annotations

```rust
let vec_of_results: <Vec<Result<i32, DivisionError>> = someIter.collect();
```


[^result]: Documentation: https://doc.rust-lang.org/std/result/enum.Result.html#impl-FromIterator%3CResult%3CA,+E%3E%3E-for-Result%3CV,+E%3E

[^vec]: Documentation: https://doc.rust-lang.org/std/vec/struct.Vec.html#impl-FromIterator%3CT%3E-for-Vec%3CT%3E