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Q&A How do I trim a sorted list in Python?

The library module itertools provides a function called dropwhile(). The example they give is: dropwhile(lambda x: x<5, [1,4,6,3,8]) → 6 3 8 So, to get a list of numbers greater than 4, d...

posted 6mo ago by aghast‭  ·  edited 6mo ago by aghast‭

Answer
#2: Post edited by user avatar aghast‭ · 2024-05-31T14:32:00Z (6 months ago)
Add hint about drop while
  • The library module [`itertools`](https://docs.python.org/3/library/itertools.html) provides a function called `dropwhile()`.
  • The example they give is:
  • dropwhile(lambda x: x<5, [1,4,6,3,8])
  • → 6 3 8
  • So, to get a list of numbers greater than 4:
  • import itertools
  • l = [1, 3, 5, 6, 7, 8]
  • result = itertools.dropwhile(lambda x: x<=4, l)
  • Note that `result` at this point will be a lazy iterator object of some kind, not an actual list. So you might have to do: `print(*result)` to confirm it works. But you can iterate it, or call `list(result)` to make it a true list. (Remember, also, that iterators get consumed.)
  • The library module [`itertools`](https://docs.python.org/3/library/itertools.html) provides a function called `dropwhile()`.
  • The example they give is:
  • dropwhile(lambda x: x<5, [1,4,6,3,8])
  • → 6 3 8
  • So, to get a list of numbers greater than 4, drop items while they are less than or equal to 4:
  • import itertools
  • l = [1, 3, 5, 6, 7, 8]
  • result = itertools.dropwhile(lambda x: x<=4, l)
  • Note that `result` at this point will be a lazy iterator object of some kind, not an actual list. So you might have to do: `print(*result)` to confirm it works. But you can iterate it, or call `list(result)` to make it a true list. (Remember, also, that iterators get consumed.)
#1: Initial revision by user avatar aghast‭ · 2024-05-31T14:30:29Z (6 months ago)
The library module [`itertools`](https://docs.python.org/3/library/itertools.html) provides a function called `dropwhile()`. 

The example they give is:

    dropwhile(lambda x: x<5, [1,4,6,3,8]) 
    → 6 3 8

So, to get a list of numbers greater than 4:

    import itertools

    l = [1, 3, 5, 6, 7, 8]
    result = itertools.dropwhile(lambda x: x<=4, l)

Note that `result` at this point will be a lazy iterator object of some kind, not an actual list. So you might have to do: `print(*result)` to confirm it works. But you can iterate it, or call `list(result)` to make it a true list. (Remember, also, that iterators get consumed.)