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I am trying to capture the content outside square brackets in groups, using this regex: (.*)\[.*?\](.*) And it works perfectly for a simple string like this: testing_[_is_]_done This is the...
#3: Post edited
by
hkotsubo
·
2024-06-14T18:24:00Z (5 months ago)
reworded title and body
Python regex capture groups dynamically
- Regex to get text outside brackets
Hello World!I am trying to capture the content outside square brackets in groups. So, this is my regex:- ```
- (.*)\[.*?\](.*)
- ```
- And it works perfectly for a simple string like this:
- ```
- testing_[_is_]_done
- ```
- This is the sample script I am using:
```- import re
- groups = re.match(r"(.*)\[.*?\](.*)", "testing_[_is_]_done").groups()
- print(groups)
- ```
- And this is the output I am getting:
```- ('testing_', '_done')
- ```
Now, the problem is, for some strings there will be multiple open-close square brackets and I am want to capture everything outside of square brackets into groups but I am not able to figure out how to come up with regex which can do this job.- This is the example:
- ```
- testing_[_is_]_done_([but need to])_handle_[this]_scenario_as_well
- ```
- And ideally, I want to capture everything outside of brackets in groups, like this:
- ```
- ('testing_', '_done_(', ')_handle_', '_scenario_as_well')
- ```
Because it can be one or n number of open-close brackets, so I am looking for a dynamic regex, but so far I am not able to find anything on it.If anyone of you have any idea on how to get this done. Kindly let me know.Thank you.
- I am trying to capture the content outside square brackets in groups, using this regex:
- ```
- (.*)\[.*?\](.*)
- ```
- And it works perfectly for a simple string like this:
- ```
- testing_[_is_]_done
- ```
- This is the sample script I am using:
- ```python
- import re
- groups = re.match(r"(.*)\[.*?\](.*)", "testing_[_is_]_done").groups()
- print(groups)
- ```
- And this is the output I am getting:
- ```none
- ('testing_', '_done')
- ```
- But for some strings there will be multiple open-close square brackets and I want to capture everything outside of square brackets into groups but I am not able to figure out how to come up with regex which can do this job.
- This is the example:
- ```
- testing_[_is_]_done_([but need to])_handle_[this]_scenario_as_well
- ```
- And ideally, I want to capture everything outside of brackets in groups, like this:
- ```
- ('testing_', '_done_(', ')_handle_', '_scenario_as_well')
- ```
- Because it can be any number of open-close brackets, so I am looking for a dynamic regex, but so far I am not able to find anything on it.
#2: Post edited
by
TonyMontana
·
2024-06-14T13:37:20Z (5 months ago)
Updated content
- Hello World!
- I am trying to capture the content outside square brackets in groups. So, this is my regex:
- ```
- (.*)\[.*?\](.*)
- ```
- And it works perfectly for a simple string like this:
- ```
- testing_[_is_]_done
- ```
- This is the sample script I am using:
- ```
- import re
- groups = re.match(r"(.*)\[.*?\](.*)", "testing_[_is_]_done").groups()
- print(groups)
- ```
- And this is the output I am getting:
- ```
- ('testing_', '_done')
- ```
- Now, the problem is, for some strings there will be multiple open-close square brackets and I am want to capture everything outside of square brackets into groups but I am not able to figure out how to come up with regex which can do this job.
Because it can one or n number of open-close brackets, so I am looking for a dynamic regex, but so far I am not able to find anything on it.- If anyone of you have any idea on how to get this done. Kindly let me know.
- Thank you.
- Hello World!
- I am trying to capture the content outside square brackets in groups. So, this is my regex:
- ```
- (.*)\[.*?\](.*)
- ```
- And it works perfectly for a simple string like this:
- ```
- testing_[_is_]_done
- ```
- This is the sample script I am using:
- ```
- import re
- groups = re.match(r"(.*)\[.*?\](.*)", "testing_[_is_]_done").groups()
- print(groups)
- ```
- And this is the output I am getting:
- ```
- ('testing_', '_done')
- ```
- Now, the problem is, for some strings there will be multiple open-close square brackets and I am want to capture everything outside of square brackets into groups but I am not able to figure out how to come up with regex which can do this job.
- This is the example:
- ```
- testing_[_is_]_done_([but need to])_handle_[this]_scenario_as_well
- ```
- And ideally, I want to capture everything outside of brackets in groups, like this:
- ```
- ('testing_', '_done_(', ')_handle_', '_scenario_as_well')
- ```
- Because it can be one or n number of open-close brackets, so I am looking for a dynamic regex, but so far I am not able to find anything on it.
- If anyone of you have any idea on how to get this done. Kindly let me know.
- Thank you.
#1: Initial revision
by
TonyMontana
·
2024-06-14T13:28:56Z (5 months ago)
Python regex capture groups dynamically
Hello World!
I am trying to capture the content outside square brackets in groups. So, this is my regex:
```
(.*)\[.*?\](.*)
```
And it works perfectly for a simple string like this:
```
testing_[_is_]_done
```
This is the sample script I am using:
```
import re
groups = re.match(r"(.*)\[.*?\](.*)", "testing_[_is_]_done").groups()
print(groups)
```
And this is the output I am getting:
```
('testing_', '_done')
```
Now, the problem is, for some strings there will be multiple open-close square brackets and I am want to capture everything outside of square brackets into groups but I am not able to figure out how to come up with regex which can do this job.
Because it can one or n number of open-close brackets, so I am looking for a dynamic regex, but so far I am not able to find anything on it.
If anyone of you have any idea on how to get this done. Kindly let me know.
Thank you.