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Q&A typeof_unqual behaves differently in gcc and clang

The C23 example as well as clang are correct. This is apparently a gcc bug in the latest 14.2 release, fixed in the "gcc (trunk)" unreleased version. The relevant part of the C23 standard here is ...

posted 16d ago by Lundin‭  ·  edited 16d ago by Lundin‭

Answer
#2: Post edited by user avatar Lundin‭ · 2024-11-26T12:20:05Z (16 days ago)
  • The C23 example as well as clang are correct. This is apparently a gcc bug in the latest 14.2 release, fixed in the "gcc (trunk)" unreleased version.
  • The relevant part of the C23 standard here is 6.7.4.1 §10:
  • > If the specification of an array type includes any type qualifiers, both the array and the element type are so-qualified.
  • (Also mentioned in 6.2.5 §31)
  • In this case the element type is `const char* const`, where the first `const` belongs to the pointed-at type and the second `const` qualifies the pointer itself. Therefore because of the second `const`, the array item is `const` qualified. And therefore, according to the quoted part above, the whole array is `const` qualified too.
  • Meaning that `typeof_unqual` should remove the `const` from the array type but not from the pointed-at item. This gives us a `const char* [3]`.
  • The C23 example as well as clang are correct. This is apparently a gcc [bug](https://gcc.gnu.org/bugzilla/show_bug.cgi?id=112841) in the latest 14.2 release, fixed in the "gcc (trunk)" unreleased version.
  • The relevant part of the C23 standard here is 6.7.4.1 §10:
  • > If the specification of an array type includes any type qualifiers, both the array and the element type are so-qualified.
  • (Also mentioned in 6.2.5 §31)
  • In this case the element type is `const char* const`, where the first `const` belongs to the pointed-at type and the second `const` qualifies the pointer itself. Therefore because of the second `const`, the array item is `const` qualified. And therefore, according to the quoted part above, the whole array is `const` qualified too.
  • Meaning that `typeof_unqual` should remove the `const` from the array type but not from the pointed-at item. This gives us a `const char* [3]`.
#1: Initial revision by user avatar Lundin‭ · 2024-11-26T12:09:12Z (16 days ago)
The C23 example as well as clang are correct. This is apparently a gcc bug in the latest 14.2 release, fixed in the "gcc (trunk)" unreleased version.

The relevant part of the C23 standard here is 6.7.4.1 §10:

> If the specification of an array type includes any type qualifiers, both the array and the element type are so-qualified.

(Also mentioned in 6.2.5 §31)

In this case the element type is `const char* const`, where the first `const` belongs to the pointed-at type and the second `const` qualifies the pointer itself. Therefore because of the second `const`, the array item is `const` qualified. And therefore, according to the quoted part above, the whole array is `const` qualified too.

Meaning that `typeof_unqual` should remove the `const` from the array type but not from the pointed-at item. This gives us a `const char* [3]`.