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Let's say we have a function void f(int argc, ...); where argc is the number of variadic arguments. Can we write a macro of the form #define F(...) f(CNT(__VA_ARGS__), __VA_ARGS__) which...
#3: Post edited
by
alx
·
2025-06-07T22:10:34Z (2 days ago)
Add CNT()
- Let's say we have a function
- ```c
- void f(int argc, ...);
- ```
- where `argc` is the number of variadic arguments.
- Can we write a macro of the form
- ```c
#define F(...) f(???, __VA_ARGS__)- ```
- which passes the right value in `argc`?
How can that be implemented?
- Let's say we have a function
- ```c
- void f(int argc, ...);
- ```
- where `argc` is the number of variadic arguments.
- Can we write a macro of the form
- ```c
- #define F(...) f(CNT(__VA_ARGS__), __VA_ARGS__)
- ```
- which passes the right value in `argc`?
- How can that `CNT()` be implemented?
#2: Post edited
by
alx
·
2025-06-07T22:09:05Z (2 days ago)
tfix
- Let's say we have a function
- ```c
- void f(int argc, ...);
- ```
- where `argc` is the number of variadic arguments.
- Can we write a macro of the form
- ```c
#define F(...) fn(???, __VA_ARGS__)- ```
- which passes the right value in `argc`?
- How can that be implemented?
- Let's say we have a function
- ```c
- void f(int argc, ...);
- ```
- where `argc` is the number of variadic arguments.
- Can we write a macro of the form
- ```c
- #define F(...) f(???, __VA_ARGS__)
- ```
- which passes the right value in `argc`?
- How can that be implemented?
#1: Initial revision
by
alx
·
2025-06-07T20:16:02Z (2 days ago)
Macro to count the number of arguments
Let's say we have a function ```c void f(int argc, ...); ``` where `argc` is the number of variadic arguments. Can we write a macro of the form ```c #define F(...) fn(???, __VA_ARGS__) ``` which passes the right value in `argc`? How can that be implemented?