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You won't be able to do it for arbitrary length tables in a single regex matching the whole row. Capture groups are replaced when repeated. So any \| (?:(cell_text) \|)+ expression[1] will wind up ...
#2: Post edited
by
Michael
·
2026-01-12T17:28:57Z (8 months ago)
You won't be able to do it for arbitrary length tables in a single regex alone. Capture groups are replaced when repeated. So any `\| (?:(cell_text) \|)+` expression[^ws] will wind up with the capture group `\g<1>` as the last cell's text.- Instead, you'd have to send, say `\|?[ \t]*(.*?)[ \t]s*\|` to `re.sub` to replace each cell in a row with `<td>\1</td>` and wrap _that_ in `<tr></tr>`.
- [^ws]: Irrespective of whitespace
- You won't be able to do it for arbitrary length tables in a single regex matching the whole row. Capture groups are replaced when repeated. So any `\| (?:(cell_text) \|)+` expression[^ws] will wind up with the capture group `\g<1>` as the last cell's text.
- Instead, you'd have to send, say `\|?[ \t]*(.*?)[ \t]s*\|` to `re.sub` to replace each cell in a row with `<td>\1</td>` and wrap _that_ in `<tr></tr>`.
- [^ws]: Irrespective of whitespace
#1: Initial revision
by
Michael
·
2026-01-12T17:28:17Z (8 months ago)
You won't be able to do it for arbitrary length tables in a single regex alone. Capture groups are replaced when repeated. So any `\| (?:(cell_text) \|)+` expression[^ws] will wind up with the capture group `\g<1>` as the last cell's text. Instead, you'd have to send, say `\|?[ \t]*(.*?)[ \t]s*\|` to `re.sub` to replace each cell in a row with `<td>\1</td>` and wrap _that_ in `<tr></tr>`. [^ws]: Irrespective of whitespace