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To expand on r's answer, the "bit of extra interpretation" might look like this: r = sp.solve([eq1, eq2]) # Solution set a_solutions = {d[a] for d in r} # Assert one solution assert len(a_so...
#2: Post edited
by
wjandrea
·
2026-07-11T13:28:08Z (2 months ago)
on second thought, don't modify the set
- To expand on [r's answer](https://software.codidact.com/posts/296349/296350#answer-296350), the "bit of extra interpretation" might look like this:
- ```py
- r = sp.solve([eq1, eq2])
- # Solution set
- a_solutions = {d[a] for d in r}
- # Assert one solution
- assert len(a_solutions) == 1
- # Extract it
a_solved = a_solutions.pop()- ```
- To expand on [r's answer](https://software.codidact.com/posts/296349/296350#answer-296350), the "bit of extra interpretation" might look like this:
- ```py
- r = sp.solve([eq1, eq2])
- # Solution set
- a_solutions = {d[a] for d in r}
- # Assert one solution
- assert len(a_solutions) == 1
- # Extract it
- a_solved = next(iter(a_solutions))
- ```
#1: Initial revision
by
wjandrea
·
2026-07-11T13:26:48Z (2 months ago)
To expand on [r's answer](https://software.codidact.com/posts/296349/296350#answer-296350), the "bit of extra interpretation" might look like this:
```py
r = sp.solve([eq1, eq2])
# Solution set
a_solutions = {d[a] for d in r}
# Assert one solution
assert len(a_solutions) == 1
# Extract it
a_solved = a_solutions.pop()
```