Here in Python, I created a program for this challenge and I'm having trouble debugging it. I already fixed most errors I have on my program but here's what I have left:

x=y=z=[];i=0.0;a=int(input());b=0
for c in range(1,a+1):
	for d in range(1,a):
		i+=1
		if a/c==i and c!=a:b+=c
	if b<a:x.append(c)
	elif b>a:y.append(c)
	else:z.append(c)
	i=b=0
print("[",end='')
for j in x:
	print(j,end='')
	if j!=len(x):print(" ",end='')
print("], [",end='')
for j in y:
	print(j,end='')
	if j!=len(y):print(" ",end='')
print("], [",end='')
for j in z:
	print(j,end='')
	if j!=len(z):print(" ",end='')
print("]",end='')

Here's the unshortened code with comments:

x=y=z=[] # Initialize up 3 empty lists
i=0.0 # initialize a float to make sure the numbers would be checked if it's a proper divisor
a=int(input()) # input an integer
b=0 # initialize the value for the proper divisor sum
for c in range(1,a+1): # start a for loop that checks which list should the number in the range of 1 and the input
	for d in range(1,a): # start a for loop to get the proper divisor sum of each number in the range of 1 and the input
		i+=1 # increment 1 for rechecking		
		if a/c==i and c!=a: # check if the number is a proper divisor
			b+=c # if it is, then add it to the sum
	if b<a:
		x.append(c) # add to the list if the number is deficient
	elif b>a:
		y.append(c) # add to the list if the number is abundant
	else:
		z.append(c) # add to the list if the number is perfect
	i=b=0 # reset the numbers for rechecking
print("[", end = '') # start the output by adding a bracket without a newline
for j in x: # print all deficient numbers as a list
	print(j, end = '') # print the number according to the for loop without a newline
	if j != len(x):
		print(" ", end = '') # print a space to separate numbers without a newline except for the last number in the list
print("], [", end = '') # End the list, proceed to the next one
for j in y: # print all abundant numbers as a list
	print(j, end = '') # print the number according to the for loop without a newline
	if j != len(y):
		print(" ", end = '') # print a space to separate numbers without a newline except for the last number in the list
print("], [", end = '') # End the list, proceed to the next one
for j in z: # print all perfect numbers as a list
	print(j, end = '') # print the number according to the for loop without a newline
	if j != len(z):
		print(" ", end = '') # print a space to separate numbers without a newline except for the last number in the list
print("]", end = '') # end it with a bracket

Basically, I'm trying to make a number checker so I can get the inputted number's proper divisor sum, which in my understanding is the sum of divisors that results in a quotient that can be formatted as n.00000..., but the resulting output leaves me with all the numbers from 1 to the input. See it for yourself! (SIFY)

I've been trying to figure out where the problem lies and I suspect it has to do with the first for loop, but I don't know where exactly to fix. Where did I mess up or how do I fix this?

posted over 3 years ago

CC BY-SA 4.0

3y ago

General Sebast1an‭

136 reputation 12 3 7 12