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Comments on Question regarding an error message in my compiler to do with my code on linked list.
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Question regarding an error message in my compiler to do with my code on linked list.
Can anyone help me, I'm currently learning pointers, this is the code I wrote to try and insert a node at the beginning of the list. However at the part where I included the comment of "error at this line" basically my compiler gave me the error of "In function Insert: Node undeclared". Why is it so?
#include<stdlib.h>
#include<stdio.h>
struct Node{
int data;
struct Node* next;
};
struct Node* head;
void Insert(int x){
Node* temp = (Node*)malloc(sizeof(struct Node)); //error at this line
temp->data = x;
temp->next = head;
head = temp;
if(head != NULL)
temp->next = head;
head = temp;
}
void Print(){
struct Node* temp = head;
printf("List is: ");
while(temp != NULL){
printf("%d", temp->data);
temp = temp->next;
}
printf("\n");
}
int main(){
head = NULL; //empty list
printf("How many numbers?\n");
int n, i;
scanf("%d", &n);
for(int i=0; i < n; i++){
printf("Enter the number\n");
scanf("%d", &x);
Insert(x);
Print();
}
}
First edit:
Update: My program runs, lets me enter the amount of numbers I want, as well as the numbers, however it prints out only the latest number I entered. What could possibly be the problem? Thanks.
#include<stdlib.h>
#include<stdio.h>
struct Node{
int data;
struct Node* next;
};
struct Node* head;
void Insert(int x){
struct Node* temp = (struct Node*)malloc(sizeof(struct Node));
temp->data = x;
temp->next = head;
head = temp;
if(head != NULL)
temp->next = head;
head = temp;
temp->next = NULL;
}
void Print(){
struct Node* temp = head;
printf("List is: ");
while(temp != NULL){
printf("%d", temp->data);
temp = temp->next;
}
printf("\n");
}
int main(){
head = NULL; //empty list
printf("How many numbers?\n");
int n, i;
scanf("%d", &n);
for(int i=0; i < n; i++){
printf("Enter the number\n");
scanf("%d", &x);
Insert(x);
Print();
}
}
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