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Comments on How can I manage multiple consecutive strings in a buffer (and add more later)?

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How can I manage multiple consecutive strings in a buffer (and add more later)?

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This question is inspired by If I have a char array containing strings with a null byte (\0) terminating each string, how would I add another string onto the end? on Stack Overflow.

Suppose I have a char[] buffer that I'm using to represent multiple null-terminated (ASCII) strings, one after the other. I can easily set up an initial state that has two strings and sufficient room to add a third:

/* The exact amount of space is not critical to the question; it's enough
   to store these strings and leave room for more. */
char buffer[80] = {'o', 'n', 'e', '\0', 't', 'w', 'o', '\0'};

Now suppose I have char* another_string = "three";. How can I append or concatenate another_string to the buffer, generally? I do not want to concatenate the three text with the two, but instead put it in the buffer as a separate string.

I already know that the <string.h> library functions expect a string to be null-terminated, so it seems like they won't help here. For example, strcat would find the first null in the array instead of the second, and overwrite it; and strncpy would need a pointer to where to start writing.

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1 comment thread

Shows why C strings are a bad idea in the first place. (1 comment)
Shows why C strings are a bad idea in the first place.

This is a good example of C-style null-terminated strings that are really just arrays of bytes are a bad idea in the first place.