As mentioned in another answer, when you have code such as if (someVar), you're subject to truthiness. To be more precise, this code will run under the rules of Boolean coercion.

In JavaScript, when you have if (someVar), the variable someVar can be basically "anything" - even a boolean value! If someVar is not a boolean, it'll be converted according to some rules:

• Booleans are returned as-is.
• undefined turns into false.
• null turns into false.
• 0, -0, and NaN turn into false; other numbers turn into true.
• 0n turns into false; other BigInts turn into true.
• The empty string "" turns into false; other strings turn into true.
• Symbols turn into true.
• All objects become true.

A little test to check this behaviour:

function test(someVar) {
    if (someVar) {
        console.log(someVar, typeof someVar, 'true');
    } else {
        console.log(someVar, typeof someVar, 'false');
    }
}

for (const v of [ null, undefined, 0, 1, '', 'abc', [], [1, 2], {} ]) {
    test(v);
}

Output:

null object false
undefined undefined false
0 number false
1 number true
 string false
abc string true
[] object true
[ 1, 2 ] object true
{} object true

Note that any object is type-coerced to true¹ (even an empty array or empty object).

  ^{1: Except, of course, null (which is an object - although it shouldn't - but it's coerced to false)}

Now back to the question: how should I check for a boolean value?

It depends!

If you know that someVar is a boolean value (either true or false, nothing else, and that's guaranteed in another part of the code), then if (someVar) is the most straighforward way to check it. You don't need anything else to verify if the value is true or false.

On the other hand, if you don't know what type someVar is (or you know, and it can be either a boolean or some other type), and you want to check if the type is boolean, then you could do something like this:

function checkBoolean(someVar) {
    if (typeof someVar === 'boolean' && someVar) {
        console.log('true');
    } else {
        console.log('false or not boolean');
    }
}

But in this case, if someVar is false, it'll enter the else clause (it's a boolean, but it's not true). If you want to differentiate between true, false and "anything else", then it should be:

function checkBoolean(someVar) {
    if (typeof someVar === 'boolean') { // it's a boolean value
        // it's either true or false
        if (someVar) {
            console.log('true');
        } else {
            console.log('false');
        }
    } else { // it's not a boolean
        console.log('not boolean');
    }
}

But if you don't care about the type of someVar and just want to know if it's "true" or "false" (according to the language's type coercion rules), if (someVar) is enough.

And of course, if you need a different check (such as "I want empty arrays to be false"), then just change the clause accordingly (ex: if (Array.isArray(someVar) ? someVar.length > 0 : someVar) - if it's an array, it can't be empty, otherwise check for truthiness).

Anyway, you must define exactly what you need: check if the type is boolean, or if the type-coerced value is true/false, or anything else (ignore null and undefined, or empty arrays can't be true, etc). Then you change the code accordingly.

Regarding the suggested code

IMO, if (typeof(someVar) !== 'undefined' || typeof(someVar) !== null || someVar !== '') is not a good way to check boolean values. Actually, I believe there's an error in this code. For example, if someVar is null, it enters the if clause:

const someVar = null;
if (typeof(someVar) !== 'undefined' || typeof(someVar) !== null || someVar !== '') {
    console.log('ok');
} else {
    console.log('not ok');
}

This code prints "ok", because typeof(null) is not null.

I believe that typeof(someVar) !== null is wrong, because it doesn't make sense: typeof anything will never be null (according to the language specification, the result of typeof is always a string).

Actually, it's worse: even if someVar is undefined or the empty string, this code will print "ok". That's because typeof(someVar) is never null, thus the condition typeof(someVar) !== null is always true. Therefore, this code is not checking anything.

posted 7 months ago

CC BY-SA 4.0

7mo ago

hkotsubo‭

5110 reputation 20 69 575 228