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Loss of precision when concatenating an exchange rate with a string

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In response to a Q on Web Applications [WA] the asker self-answered with:

=CONCATENATE("@ £/€ rate: ",text(J21,"0.00000"))

The issue was that, with "in a cell J21 I have a set value 1.10000":.

=CONCATENATE("@ £/€ rate: ",(J21))

was returning @ £/€ rate: 1.1 rather than @ £/€ rate: 1.10000.

Is there a shorter and/or clearer formula to the same effect?

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