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Q&A

What does the greater than 0 indicate in the case of this statement 'if (compare(A[j], A[j+1]) > 0)' ? Thank you.

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Question: There is a list of integers in an array (3,2,1,5,6,4), sort this list in both ASCENDING & DESCENDING order. Create a sort function.

#include<stdio.h>
#include<stdlib.h>

void BubbleSort (int A[], int n, int (*compare)(int, int)){

int i,j,temp;        
    for (i=0; i<n; i++){  
        for(j=0; j<n-1; j++){ 
            if (compare(A[j], A[j+1]) > 0){ //regarding this line of code
                temp = A[j];
                A[j] = A[j+1];
                A[j+1] = temp;
            }
         }
    }
}

int main (){

    int i, A[] = {3,2,1,5,6,4};
    BubbleSort(A,6);     
    for (i=0; i<6; i++){
        printf("%d", A[i]);
    }
}
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1 answer

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Generally speaking, comparison callback functions in C are often implemented to return an integer lesser than zero, equal to zero or greater than zero - depending on if the first object is lesser than, equal to or greater than the second object.

How it is done in your case, there's no telling since you didn't post the comparison function and the call BubbleSort(A,6); is also invalid.

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