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I want a way to make it so that I can use list B to find out if a copy of itself exists in list A. listA = ['1', '1', '0', '1', '0', '1', 'down'] 2 ['0', '0', '1', '1', '1', '1', 'up'] 2 ['1', '...
#3: Post edited
by
Alexei
·
2022-10-25T16:54:41Z (over 1 year ago)
Fixed the code and minor spelling error fix
i want a way to make it so that i can use list B to find out if a copy of it's self exists in list A.- listA = ['1', '1', '0', '1', '0', '1', 'down'] 2
- ['0', '0', '1', '1', '1', '1', 'up'] 2
- ['1', '0', '0', '1', '0', '1', 'up'] 1
- ['0', '0', '0', '1', '1', '0', 'up'] 2
- ['1', '1', '0', '0', '0', '0', 'up'] 1
- ['0', '0', '1', '1', '0', '1', 'down'] 1
- ['1', '0', '0', '0', '0', '1', 'down'] 1
- ['1', '1', '1', '1', '1', '1', 'up'] 1
- listB = ['1', '1', '1', '1', '1', '1']
- list A also shows how many times that particular list has appeared
so i want a way to first find the repeating list of list B in list A, secondly to select the one with the most repetitions in the case that there are multiple versions of it.
- I want a way to make it so that I can use list B to find out if a copy of itself exists in list A.
- ```
- listA = ['1', '1', '0', '1', '0', '1', 'down'] 2
- ['0', '0', '1', '1', '1', '1', 'up'] 2
- ['1', '0', '0', '1', '0', '1', 'up'] 1
- ['0', '0', '0', '1', '1', '0', 'up'] 2
- ['1', '1', '0', '0', '0', '0', 'up'] 1
- ['0', '0', '1', '1', '0', '1', 'down'] 1
- ['1', '0', '0', '0', '0', '1', 'down'] 1
- ['1', '1', '1', '1', '1', '1', 'up'] 1
- listB = ['1', '1', '1', '1', '1', '1']
- ```
- list A also shows how many times that particular list has appeared
- So, I want a way to first find the repeating list of list B in list A, and secondly to select the one with the most repetitions in the case that there are multiple versions of it.
#2: Post edited
by
Alexei
·
2022-10-25T16:50:18Z (over 1 year ago)
fixed the tags
#1: Initial revision
by
Solaranfel1366
·
2022-10-25T16:09:03Z (over 1 year ago)
how to use one list to find a similar list in another list python
i want a way to make it so that i can use list B to find out if a copy of it's self exists in list A. listA = ['1', '1', '0', '1', '0', '1', 'down'] 2 ['0', '0', '1', '1', '1', '1', 'up'] 2 ['1', '0', '0', '1', '0', '1', 'up'] 1 ['0', '0', '0', '1', '1', '0', 'up'] 2 ['1', '1', '0', '0', '0', '0', 'up'] 1 ['0', '0', '1', '1', '0', '1', 'down'] 1 ['1', '0', '0', '0', '0', '1', 'down'] 1 ['1', '1', '1', '1', '1', '1', 'up'] 1 listB = ['1', '1', '1', '1', '1', '1'] list A also shows how many times that particular list has appeared so i want a way to first find the repeating list of list B in list A, secondly to select the one with the most repetitions in the case that there are multiple versions of it.