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how to use one list to find a similar list in another list python

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I want a way to make it so that I can use list B to find out if a copy of itself exists in list A.

listA = ['1', '1', '0', '1', '0', '1', 'down'] 2
['0', '0', '1', '1', '1', '1', 'up'] 2
['1', '0', '0', '1', '0', '1', 'up'] 1
['0', '0', '0', '1', '1', '0', 'up'] 2
['1', '1', '0', '0', '0', '0', 'up'] 1
['0', '0', '1', '1', '0', '1', 'down'] 1
['1', '0', '0', '0', '0', '1', 'down'] 1
['1', '1', '1', '1', '1', '1', 'up'] 1

listB = ['1', '1', '1', '1', '1', '1']

list A also shows how many times that particular list has appeared

So, I want a way to first find the repeating list of list B in list A, and secondly to select the one with the most repetitions in the case that there are multiple versions of it.

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Sorry, I don't get it. Please provide an example of the inputs and the expected output. Moreover, a... (3 comments)

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